Problem

Solve for k (k+1)/2+(k+3)/4=1/2

The question provided is a linear algebraic equation involving a variable k. You are asked to solve for the value of k that makes the equation true. The equation includes fractions and the variable k is found in two different terms on the left side of the equation. To find the value of k, you would typically need to manipulate the equation using algebraic techniques to isolate k on one side of the equation.

$\frac{k + 1}{2} + \frac{k + 3}{4} = \frac{1}{2}$

Answer

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Solution:

Step:1

Transform $\frac{k + 1}{2} + \frac{k + 3}{4}$ into a single fraction.

Step:1.1

Convert $\frac{k + 1}{2}$ to have a denominator of $4$ by multiplying by $\frac{2}{2}$. $\frac{k + 1}{2} \cdot \frac{2}{2} + \frac{k + 3}{4} = \frac{1}{2}$

Step:1.2

Adjust each term to a denominator of $4$.

Step:1.2.1

Scale $\frac{k + 1}{2}$ by $\frac{2}{2}$. $\frac{(k + 1) \cdot 2}{2 \cdot 2} + \frac{k + 3}{4} = \frac{1}{2}$

Step:1.2.2

Multiply $2$ by itself. $\frac{(k + 1) \cdot 2}{4} + \frac{k + 3}{4} = \frac{1}{2}$

Step:1.3

Merge the numerators over the shared denominator. $\frac{(k + 1) \cdot 2 + k + 3}{4} = \frac{1}{2}$

Step:1.4

Streamline the numerator.

Step:1.4.1

Employ the distributive law. $\frac{k \cdot 2 + 1 \cdot 2 + k + 3}{4} = \frac{1}{2}$

Step:1.4.2

Reposition $2$ before $k$. $\frac{2 \cdot k + 2 + k + 3}{4} = \frac{1}{2}$

Step:1.4.3

Execute the multiplication of $2$ by $1$. $\frac{2 \cdot k + 2 + k + 3}{4} = \frac{1}{2}$

Step:1.4.4

Combine $2k$ with $k$. $\frac{3k + 5}{4} = \frac{1}{2}$

Step:2

Cross-multiply by $4$. $\frac{3k + 5}{4} \cdot 4 = \frac{1}{2} \cdot 4$

Step:3

Condense the equation.

Step:3.1

Refine the left-hand side.

Step:3.1.1

Eliminate the $4$.

Step:3.1.1.1

Remove the $4$. $\frac{3k + 5}{\cancel{4}} \cdot \cancel{4} = \frac{1}{2} \cdot 4$

Step:3.1.1.2

Express the simplified form. $3k + 5 = 2$

Step:3.2

Clarify the right-hand side.

Step:3.2.1

Extract the $2$.

Step:3.2.1.1

Isolate $2$ from $4$. $3k + 5 = \frac{1}{2} \cdot (2 \cdot 2)$

Step:3.2.1.2

Cancel out the $2$. $3k + 5 = 1 \cdot (2)$

Step:3.2.1.3

Rephrase the expression. $3k + 5 = 2$

Step:4

Determine the value of $k$.

Step:4.1

Shift constants to the opposite side.

Step:4.1.1

Subtract $5$ on both sides. $3k = 2 - 5$

Step:4.1.2

Compute $2 - 5$. $3k = -3$

Step:4.2

Divide the equation by $3$.

Step:4.2.1

Divide $3k$ and $-3$ by $3$. $\frac{3k}{3} = \frac{-3}{3}$

Step:4.2.2

Simplify the left-hand side.

Step:4.2.2.1

Remove the $3$. $\frac{\cancel{3}k}{\cancel{3}} = \frac{-3}{3}$

Step:4.2.3

Simplify the right-hand side.

Step:4.2.3.1

Divide $-3$ by $3$. $k = -1$

Knowledge Notes:

The problem involves solving a linear equation with fractions. The key knowledge points include:

  1. Common Denominator: To combine fractions, they must have the same denominator. Multiplying by a form of one (e.g., $\frac{2}{2}$) that does not change the value of the fraction is used to achieve this.

  2. Distributive Property: This property is used to simplify expressions, such as $2(k + 1)$, which becomes $2k + 2$.

  3. Cross-Multiplication: When two fractions are set equal to each other, you can cross-multiply to eliminate the denominators.

  4. Simplifying Equations: This involves canceling out common factors on both sides of the equation to isolate the variable.

  5. Solving Linear Equations: The goal is to isolate the variable (in this case, $k$) by performing inverse operations (addition/subtraction, multiplication/division) on both sides of the equation.

Understanding these concepts is crucial for solving linear equations and working with algebraic expressions involving fractions.

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