Evaluate square root of 7^2+1^2
The question is asking for the computation of the square root of the sum of the squares of two numbers: 7 and 1. Specifically, you are to first square each number (7^2 and 1^2), add these values together, and then find the square root of this resulting sum.
$\sqrt{7^{2} + 1^{2}}$
Square the number $7$. $\sqrt{49 + 1^2}$
Any number raised to the power of one remains the same. $\sqrt{49 + 1}$
Combine $49$ and $1$. $\sqrt{50}$
Express $50$ as the product of $5^2$ and $2$.
Extract the square of $5$ from the product. $\sqrt{25 \cdot 2}$
Represent $25$ as $5^2$. $\sqrt{5^2 \cdot 2}$
Remove the square root from the squared term. $5\sqrt{2}$
Present the solution in its various forms.
Exact Form: $5\sqrt{2}$ Decimal Form: Approximately $7.07106781$
To solve a problem involving the square root of the sum of squares, we follow these steps:
Squaring Numbers: When a number is squared, it is multiplied by itself. For example, $7^2 = 7 \times 7 = 49$.
Exponent Laws: Any number raised to the power of $1$ remains unchanged, as $n^1 = n$ for any number $n$.
Simplifying Square Roots: When simplifying the square root of a product, if one of the factors is a perfect square, it can be taken out of the square root as its base. For example, $\sqrt{a^2 \cdot b} = a\sqrt{b}$ if $a$ is an integer.
Combining Like Terms: Arithmetic operations such as addition must be performed before taking the square root.
Square Root of a Product: The square root of a product $\sqrt{a \cdot b}$ can be expressed as $\sqrt{a} \cdot \sqrt{b}$ if both $a$ and $b$ are non-negative.
Exact and Decimal Forms: The exact form of a square root is the simplified radical expression, while the decimal form is the approximate numerical value, which can be found using a calculator.
In this problem, we use these principles to simplify the expression $\sqrt{7^2 + 1^2}$, ultimately finding that it equals $5\sqrt{2}$ in exact form and approximately $7.07106781$ in decimal form.