Solve for x 1/5-(x-4)/10=1+(x-2)/2
The given problem is an algebraic equation that requires finding the value of the variable x. The equation consists of a fraction and two rational expressions where x is a part of both the numerator and the denominator. The task is to perform the necessary algebraic manipulations such as finding a common denominator, combining like terms, and isolating x on one side of the equation to solve for its value. This may involve simplifying the equation, using addition or subtraction to combine terms, and using multiplication or division to solve for x.
$\frac{1}{5} - \frac{x - 4}{10} = 1 + \frac{x - 2}{2}$
Transform $\frac{1}{5} - \frac{x - 4}{10}$ to have a common denominator.
Convert $\frac{1}{5}$ to have a denominator of $10$ by multiplying it by $\frac{2}{2}$: $\frac{1}{5} \cdot \frac{2}{2} - \frac{x - 4}{10} = 1 + \frac{x - 2}{2}$
Ensure all terms have a denominator of $10$.
Multiply $\frac{1}{5}$ by $\frac{2}{2}$ to get $\frac{2}{10} - \frac{x - 4}{10} = 1 + \frac{x - 2}{2}$
Multiply $5$ by $2$ to confirm the common denominator: $\frac{2}{10} - \frac{x - 4}{10} = 1 + \frac{x - 2}{2}$
Add the numerators over the shared denominator: $\frac{2 - (x - 4)}{10} = 1 + \frac{x - 2}{2}$
Simplify the numerator by distributing.
Distribute the negative sign: $\frac{2 - x + 4}{10} = 1 + \frac{x - 2}{2}$
Combine like terms in the numerator: $\frac{6 - x}{10} = 1 + \frac{x - 2}{2}$
Extract common factors if possible.
Factor out $-1$ from $-x$: $\frac{-1(x - 6)}{10} = 1 + \frac{x - 2}{2}$
Rewrite the expression: $- \frac{x - 6}{10} = 1 + \frac{x - 2}{2}$
Simplify $1 + \frac{x - 2}{2}$.
Combine into a single fraction.
Express $1$ as a fraction with a denominator of $2$: $- \frac{x - 6}{10} = \frac{2}{2} + \frac{x - 2}{2}$
Add the numerators together: $- \frac{x - 6}{10} = \frac{x}{2}$
Simplify the numerator.
Subtract $2$ from $2$: $- \frac{x - 6}{10} = \frac{x}{2}$
Isolate all $x$ terms on one side.
Subtract $\frac{x}{2}$ from both sides: $- \frac{x - 6}{10} - \frac{x}{2} = 0$
Convert $- \frac{x}{2}$ to have a denominator of $10$ by multiplying by $\frac{5}{5}$: $- \frac{x - 6}{10} - \frac{x \cdot 5}{10} = 0$
Combine the numerators over the common denominator: $\frac{- (x - 6) - 5x}{10} = 0$
Simplify the numerator by distributing and combining like terms: $\frac{-6x + 6}{10} = 0$
Factor out common terms if possible.
Factor out $6$: $\frac{6(-x + 1)}{10} = 0$
Reduce the fraction by canceling common factors.
Divide both the numerator and the denominator by $2$: $\frac{3(-x + 1)}{5} = 0$
Simplify further if possible: $- \frac{3(x - 1)}{5} = 0$
Set the numerator equal to zero to solve for $x$: $3(x - 1) = 0$
Find the value of $x$.
Divide each term by $3$ and simplify.
Divide the equation by $3$: $x - 1 = 0$
Add $1$ to both sides to isolate $x$: $x = 1$
This problem involves solving a linear equation with fractions. Here are the relevant knowledge points:
Common Denominator: When adding or subtracting fractions, it's necessary to have a common denominator. This allows you to combine the fractions by adding or subtracting the numerators.
Distributive Property: This property is used to multiply a single term by each term inside a set of parentheses. For example, $a(b + c) = ab + ac$.
Combining Like Terms: This refers to the process of adding or subtracting terms that have the same variable raised to the same power.
Factoring: Factoring involves expressing an expression as the product of its factors. This can simplify the expression and is often used before canceling common factors.
Reducing Fractions: When a numerator and denominator share a common factor, they can be divided by that factor to simplify the fraction.
Solving Linear Equations: To solve for a variable, you need to isolate it on one side of the equation, often by using inverse operations like addition/subtraction or multiplication/division.