Rationalize the Denominator cube root of 2/4
The problem presented is a mathematical expression that requires a process called "rationalizing the denominator." The expression given is the fraction where the numerator is the cube root of 2, and the denominator is the number 4. The question asks to rewrite this expression so that the denominator is a rational number instead of a radical. This typically involves manipulating the expression so that the radical is eliminated from the bottom of the fraction.
$\sqrt[3]{\frac{2}{4}}$
Reduce the common factors in the numerator and denominator.
Extract the factor of 2 from the numerator. $\sqrt[3]{\frac{2 \cdot 1}{4}}$
Factor 2 out of 4. $\sqrt[3]{\frac{2 \cdot 1}{2 \cdot 2}}$
Remove the common factor of 2. $\sqrt[3]{\frac{\cancel{2} \cdot 1}{\cancel{2} \cdot 2}}$
The expression becomes $\sqrt[3]{\frac{1}{2}}$.
Split the cube root of the fraction into separate cube roots. $\frac{\sqrt[3]{1}}{\sqrt[3]{2}}$
Recognize that the cube root of 1 is 1. $\frac{1}{\sqrt[3]{2}}$
Multiply by the conjugate cube root over itself. $\frac{1}{\sqrt[3]{2}} \cdot \frac{\left(\sqrt[3]{2}\right)^{2}}{\left(\sqrt[3]{2}\right)^{2}}$
Multiply the terms. $\frac{\left(\sqrt[3]{2}\right)^{2}}{\sqrt[3]{2} \cdot \left(\sqrt[3]{2}\right)^{2}}$
Raise the cube root to the power of 1. $\frac{\left(\sqrt[3]{2}\right)^{2}}{\left(\sqrt[3]{2}\right)^{1} \cdot \left(\sqrt[3]{2}\right)^{2}}$
Use the exponent rule to combine terms. $\frac{\left(\sqrt[3]{2}\right)^{2}}{\left(\sqrt[3]{2}\right)^{1 + 2}}$
Add the exponents. $\frac{\left(\sqrt[3]{2}\right)^{2}}{\left(\sqrt[3]{2}\right)^{3}}$
Express the cube root as an exponent. $\frac{\left(\sqrt[3]{2}\right)^{2}}{\left(2^{\frac{1}{3}}\right)^{3}}$
Multiply the exponents. $\frac{\left(\sqrt[3]{2}\right)^{2}}{2^{\frac{1}{3} \cdot 3}}$
Combine the terms. $\frac{\left(\sqrt[3]{2}\right)^{2}}{2^{\frac{3}{3}}}$
Remove the common factor of 3. $\frac{\left(\sqrt[3]{2}\right)^{2}}{2^{\frac{\cancel{3}}{\cancel{3}}}}$
The expression simplifies to $\frac{\left(\sqrt[3]{2}\right)^{2}}{2}$.
Express the squared cube root as a cube root of a square. $\frac{\sqrt[3]{2^2}}{2}$
Square the number 2. $\frac{\sqrt[3]{4}}{2}$
Exact Form: $\frac{\sqrt[3]{4}}{2}$ Decimal Form: $0.79370052 \ldots$
Rationalizing the Denominator: This process involves removing the radical (in this case, a cube root) from the denominator of a fraction. This is typically done by multiplying the fraction by a form of 1 that contains the radical in both the numerator and the denominator, thus eliminating the radical in the denominator after simplification.
Cube Root: The cube root of a number $a$, denoted as $\sqrt[3]{a}$, is a value that, when multiplied by itself three times, gives the number $a$. The cube root of 1 is always 1.
Exponent Rules: When multiplying like bases, you add the exponents: $a^m \cdot a^n = a^{m+n}$. When raising a power to a power, you multiply the exponents: $(a^m)^n = a^{mn}$.
Simplifying Fractions: To simplify a fraction, you divide the numerator and the denominator by their greatest common factor.
Conjugate Cube Roots: To rationalize a cube root in the denominator, you multiply by the square of the cube root over itself, which is the conjugate in terms of cube roots. This is because $(\sqrt[3]{a})^3 = a$, which eliminates the cube root when in the denominator.
Decimal Form: The exact form of a radical expression can be approximated by a decimal, which is often more useful for practical calculations. However, this form is an approximation and not exact.