Graph y> =(-1/3)x+4
The question presents a relational expression involving a graph and asks to illustrate the set of points (x, y) on a Cartesian plane that satisfy the inequality y is greater than or equal to (-1/3)x + 4. This involves plotting the line y = (-1/3)x + 4, which represents the boundary of the inequality, and then shading the region above the line to indicate all the points where the y-values are greater than those on the line, adhering to the inequality given.
Step 1.1: Isolate
Step 1.1.1: Multiply
Step 1.1.2: Rewrite the inequality as
Step 1.2: Arrange the terms in the standard form
Step 1.3: Simplify to remove any parentheses, resulting in
Step 2.1: Determine the slope
Step 2.2: Note that the slope of the line is
Graph the line with a solid border to represent
Since
To graph an inequality in two variables (like
Slope-Intercept Form: The slope-intercept form of a line is
Slope: The slope of a line (
Y-Intercept: The y-intercept (
Graphing Inequalities: When graphing an inequality, you use a solid line if the inequality includes equal to (鈮?or 鈮?, and a dashed line if it does not (> or <). The area above or below the line is shaded to represent all the solutions to the inequality. If the inequality is
Boundary Line: The line itself is called the boundary line because it represents the exact points where the inequality is true when it includes an equal sign (鈮?or 鈮?.