Problem

Simplify (x+1)/(x+2)+1/((x+1)/(x+2))

The question is asking you to perform algebraic manipulation on a given complex rational expression. Specifically, you are to take the sum of a fraction, (x+1)/(x+2), and the reciprocal of that same fraction, 1/((x+1)/(x+2)), and simplify the result into a more straightforward or reduced form. Simplification may involve finding a common denominator, combining like terms, and reducing the expression wherever possible to express the final result in the simplest form.

x+1x+2+1x+1x+2

Answer

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Solution:

Step:1

Break down the expression into simpler components.

Step:1.1

Take the reciprocal of the second term and multiply it with the first term. x+1x+2+x+2x+1

Step:1.2

Rewrite 1 as x+2x+1 to combine the terms. x+1x+2+x+2x+1

Step:2

Create a common denominator for x+1x+2 by multiplying it by x+1x+1. x+1x+2x+1x+1+x+2x+1

Step:3

Create a common denominator for x+2x+1 by multiplying it by x+2x+2. x+1x+2x+1x+1+x+2x+1x+2x+2

Step:4

Combine the terms over a common denominator of (x+2)(x+1).

Step:4.1

Multiply x+1x+2 by x+1x+1. (x+1)(x+1)(x+2)(x+1)+x+2x+1x+2x+2

Step:4.2

Multiply x+2x+1 by x+2x+2. (x+1)(x+1)(x+2)(x+1)+(x+2)(x+2)(x+1)(x+2)

Step:4.3

Rearrange the factors of (x+2)(x+1). (x+1)(x+1)(x+1)(x+2)+(x+2)(x+2)(x+1)(x+2)

Step:5

Combine the numerators over the common denominator. (x+1)(x+1)+(x+2)(x+2)(x+1)(x+2)

Step:6

Expand and simplify the numerator.

Step:6.1

Use the FOIL Method to expand (x+1)(x+1).

Step:6.1.1

Distribute each term in the first binomial across the second. x(x+1)+1(x+1)+(x+2)(x+2)(x+1)(x+2)

Step:6.1.2

Distribute x across (x+1). xx+x1+1(x+1)+(x+2)(x+2)(x+1)(x+2)

Step:6.1.3

Distribute 1 across (x+1). xx+x1+1x+11+(x+2)(x+2)(x+1)(x+2)

Step:6.2

Combine like terms and simplify.

Step:6.2.1

Simplify each term.

Step:6.2.1.1

Square x. x2+x1+1x+11+(x+2)(x+2)(x+1)(x+2)

Step:6.2.1.2

Multiply x by 1. x2+x+1x+11+(x+2)(x+2)(x+1)(x+2)

Step:6.2.1.3

Multiply 1 by 1. x2+x+x+1+(x+2)(x+2)(x+1)(x+2)

Step:6.2.2

Add x and x. x2+2x+1+(x+2)(x+2)(x+1)(x+2)

Step:6.3

Use the FOIL Method to expand (x+2)(x+2).

Step:6.3.1

Distribute each term in the first binomial across the second. x2+2x+1+x(x+2)+2(x+2)(x+1)(x+2)

Step:6.3.2

Distribute x across (x+2). x2+2x+1+xx+x2+2(x+2)(x+1)(x+2)

Step:6.3.3

Distribute 2 across (x+2). x2+2x+1+xx+x2+2x+22(x+1)(x+2)

Step:6.4

Combine like terms and simplify.

Step:6.4.1

Simplify each term.

Step:6.4.1.1

Square x. x2+2x+1+x2+x2+2x+22(x+1)(x+2)

Step:6.4.1.2

Multiply 2 by x. x2+2x+1+x2+2x+2x+22(x+1)(x+2)

Step:6.4.1.3

Multiply 2 by 2. x2+2x+1+x2+2x+2x+4(x+1)(x+2)

Step:6.4.2

Add 2x and 2x. x2+2x+1+x2+4x+4(x+1)(x+2)

Step:6.5

Add x2 and x2. 2x2+2x+1+4x+4(x+1)(x+2)

Step:6.6

Add 2x and 4x. 2x2+6x+1+4(x+1)(x+2)

Step:6.7

Add 1 and 4. 2x2+6x+5(x+1)(x+2)

Knowledge Notes:

  1. Reciprocal: The reciprocal of a number or a fraction is the inverse of it. For a fraction, you flip the numerator and denominator to find its reciprocal.

  2. Common Denominator: When adding or subtracting fractions, a common denominator is required. It is the product of the denominators of the fractions involved.

  3. FOIL Method: A technique for multiplying two binomials. FOIL stands for First, Outer, Inner, Last, referring to the terms that are multiplied together.

  4. Distributive Property: This property states that a(b+c)=ab+ac. It is used to multiply a single term by each term inside a parenthesis.

  5. Combining Like Terms: This involves adding or subtracting terms that have the same variable raised to the same power.

  6. Simplifying Expressions: The process of reducing an expression to its simplest form by performing all possible operations and combining like terms.

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