Simplify 12 root of (81x^4y^12)/(16c^8d^4)
The question asks to simplify the mathematical expression given. It involves a radical, specifically the 12th root of a fraction. The numerator of the fraction is 81x^4y^12, and the denominator is 16c^8d^4. The simplification process would likely involve reducing the fraction inside the radical by finding common factors, applying the properties of exponents, and possibly separating the radical into simpler parts or individual roots if applicable. The simplification must comply with the rules of radicals and exponents to reach the most reduced form of the expression.
$\sqrt[12]{\frac{81 x^{4} y^{12}}{16 c^{8} d^{4}}}$
Express $81x^4y^{12}$ as $(3xy^3)^4$. Evaluate $\sqrt[12]{\frac{(3xy^3)^4}{16c^8d^4}}$.
Express $16c^8d^4$ as $(2c^2d)^4$. Evaluate $\sqrt[12]{\frac{(3xy^3)^4}{(2c^2d)^4}}$.
Combine the terms under the radical sign as $(\frac{3xy^3}{2c^2d})^4$. Evaluate $\sqrt[12]{(\frac{3xy^3}{2c^2d})^4}$.
Convert the 12th root to a cube root of a fourth root: $\sqrt[3]{\sqrt[4]{(\frac{3xy^3}{2c^2d})^4}}$.
Extract terms from under the radical, assuming all variables represent positive real numbers: $\sqrt[3]{\frac{3xy^3}{2c^2d}}$.
Separate the cube root in the numerator and denominator: $\frac{\sqrt[3]{3xy^3}}{\sqrt[3]{2c^2d}}$.
Simplify the numerator.
Reorganize $3xy^3$ as $y^3 \cdot (3x)$.
Rearrange to $\frac{\sqrt[3]{3y^3x}}{\sqrt[3]{2c^2d}}$.
Switch the order of $3$ and $y^3$: $\frac{\sqrt[3]{y^3 \cdot 3x}}{\sqrt[3]{2c^2d}}$.
Enclose with parentheses: $\frac{\sqrt[3]{y^3 \cdot (3x)}}{\sqrt[3]{2c^2d}}$.
Extract terms from under the cube root: $\frac{y\sqrt[3]{3x}}{\sqrt[3]{2c^2d}}$.
Multiply by $\frac{(\sqrt[3]{2c^2d})^2}{(\sqrt[3]{2c^2d})^2}$: $\frac{y\sqrt[3]{3x}}{\sqrt[3]{2c^2d}} \cdot \frac{(\sqrt[3]{2c^2d})^2}{(\sqrt[3]{2c^2d})^2}$.
Combine and simplify the denominator.
Multiply: $\frac{y\sqrt[3]{3x}(\sqrt[3]{2c^2d})^2}{\sqrt[3]{2c^2d}(\sqrt[3]{2c^2d})^2}$.
Raise $\sqrt[3]{2c^2d}$ to the power of $1$: $\frac{y\sqrt[3]{3x}(\sqrt[3]{2c^2d})^2}{(\sqrt[3]{2c^2d})^1(\sqrt[3]{2c^2d})^2}$.
Apply the power rule $a^ma^n = a^{m+n}$: $\frac{y\sqrt[3]{3x}(\sqrt[3]{2c^2d})^2}{(\sqrt[3]{2c^2d})^{1+2}}$.
Add the exponents: $\frac{y\sqrt[3]{3x}(\sqrt[3]{2c^2d})^2}{(\sqrt[3]{2c^2d})^3}$.
Convert the cube root to its equivalent power: $\frac{y\sqrt[3]{3x}(\sqrt[3]{2c^2d})^2}{(2c^2d)^1}$.
Simplify the numerator.
Express $(\sqrt[3]{2c^2d})^2$ as $\sqrt[3]{(2c^2d)^2}$: $\frac{y\sqrt[3]{3x}\sqrt[3]{(2c^2d)^2}}{2c^2d}$.
Apply the product rule to $2c^2d$: $\frac{y\sqrt[3]{3x}\sqrt[3]{(2c^2)^2d^2}}{2c^2d}$.
Apply the product rule to $2c^2$: $\frac{y\sqrt[3]{3x}\sqrt[3]{4(c^2)^2d^2}}{2c^2d}$.
Square $2$: $\frac{y\sqrt[3]{3x}\sqrt[3]{4c^4d^2}}{2c^2d}$.
Combine the exponents in $c^4$.
Apply the power rule: $\frac{y\sqrt[3]{3x}\sqrt[3]{4c^{4}d^2}}{2c^2d}$.
Multiply the exponents: $\frac{y\sqrt[3]{3x}\sqrt[3]{4c^{4}d^2}}{2c^2d}$.
Cancel the common factors of $c$.
Factor $c$ out of the numerator: $\frac{c(y\sqrt[3]{12xcd^2})}{2c^2d}$.
Cancel the common $c$ factors: $\frac{y\sqrt[3]{12xcd^2}}{2cd}$.
Radical Simplification: The process involves expressing numbers as powers of their prime factors and simplifying under the radical sign.
Cube and Fourth Roots: These are specific types of radicals where the index is 3 (cube root) or 4 (fourth root).
Rationalizing the Denominator: Multiplying by a form of one to eliminate radicals from the denominator.
Power Rule: For any real number $a$ and integers $m$ and $n$, $a^m \cdot a^n = a^{m+n}$.
Product Rule for Radicals: For any nonnegative real numbers $a$ and $b$, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$.
Cancellation: If a factor appears in both the numerator and denominator, it can be canceled out.
Assumption of Positive Real Numbers: When simplifying radicals, it is typically assumed that all variables represent positive real numbers to avoid dealing with complex numbers.