Problem

Solve by Completing the Square 1=x^2-6x

The problem presented requires the solution of a quadratic equation by the method of completing the square. The quadratic equation is in the form of ax2+bx+c=0, where a, b, and c are constants. Specifically, the given equation is 1=x26x. To solve this equation by completing the square, one must manipulate the equation to express the left-hand side as a perfect square trinomial, which will allow the square root to be taken on both sides of the equation and thus isolating x to find the solutions. The completion of the square involves adding and subtracting the same value to preserve the original equation's integrity.

1=x26x

Answer

Expert–verified

Solution:

Step 1:

Move the x terms to the left by reversing the equation: x26x=1.

Step 2:

Determine the number to complete the square, which is (b2)2=(3)2.

Step 3:

Add this number to both sides of the equation: x26x+(3)2=1+(3)2.

Step 4:

Simplify both sides of the equation.

Step 4.1:

On the left, combine like terms.

Step 4.1.1:

Calculate (3)2: x26x+9=1+(3)2.

Step 4.2:

On the right, simplify the expression.

Step 4.2.1:

Evaluate 1+(3)2.

Step 4.2.1.1:

Square 3: x26x+9=1+9.

Step 4.2.1.2:

Add 1 and 9: x26x+9=10.

Step 5:

Factor the left side as a binomial square: (x3)2=10.

Step 6:

Solve for x.

Step 6.1:

Take the square root of both sides: x3=±10.

Step 6.2:

Isolate x by adding 3 to both sides: x=±10+3.

Step 7:

Present the solution in its exact and decimal forms.

Exact Form: x=±10+3 Decimal Form: x=6.16227766,0.16227766

Knowledge Notes:

To solve a quadratic equation by completing the square, one must manipulate the equation to form a perfect square trinomial on one side. The steps typically involve:

  1. Ensuring the quadratic term has a coefficient of 1.

  2. Moving the constant term to the opposite side of the equation.

  3. Finding the value needed to complete the square, which is (b2)2, where b is the coefficient of the x term.

  4. Adding this value to both sides of the equation.

  5. Factoring the perfect square trinomial on one side.

  6. Taking the square root of both sides to solve for x.

  7. Isolating x and simplifying as needed.

In this case, the quadratic equation is x26x=1. The value needed to complete the square is (3)2=9. After adding 9 to both sides and factoring, we get (x3)2=10. Taking the square root gives x3=±10, and adding 3 to both sides gives the solutions x=±10+3. The decimal form of the solutions can be found using a calculator.

link_gpt