Find the x and y Intercepts f(x)=-1/4e^(x-3)
The question is asking for the identification of the points on the coordinate plane where the graph of the given function f(x) = -1/4 * e^(x-3) crosses the x-axis and y-axis. The x-intercept(s) refers to the point(s) where the function has a value of zero (where the graph crosses the x-axis), and the y-intercept is the point where the graph of the function crosses the y-axis, which occurs when the value of x is zero.
$f \left(\right. x \left.\right) = - \frac{1}{4} e^{x - 3}$
$$0 = -\frac{1}{4}e^{x-3}$$
$$-\frac{1}{4}e^{x-3} = 0$$
$$-4(-\frac{1}{4}e^{x-3}) = -4(0)$$
$$-4(-\frac{e^{x-3}}{4}) = 0$$
$$e^{x-3} = 0$$
$$e^{x-3} = 0$$
$$\ln(e^{x-3}) = \ln(0)$$
Undefined
No solution
x-intercepts: None
$$y = -\frac{1}{4}e^{0-3}$$
$$y = -\frac{1}{4}e^{-3}$$
$$y = -\frac{1}{4} \cdot \frac{1}{e^3}$$
$$y = -\frac{1}{4e^3}$$
y-intercepts: $(0, -\frac{1}{4e^3})$
x-intercepts: None y-intercepts: $(0, -\frac{1}{4e^3})$
x-intercepts: Points where the graph of a function crosses the x-axis. To find them, set $y=0$ and solve for $x$.
y-intercepts: Points where the graph of a function crosses the y-axis. To find them, set $x=0$ and solve for $y$.
Exponential functions: Functions of the form $f(x) = a \cdot e^{bx+c}$, where $e$ is the base of the natural logarithm.
Natural logarithm: The logarithm to the base $e$, denoted as $\ln(x)$. It is the inverse operation to taking the power of $e$.
Undefined logarithms: The natural logarithm of zero, $\ln(0)$, is undefined because there is no number that $e$ can be raised to in order to get zero.
Negative exponent rule: For any nonzero number $b$ and positive integer $n$, $b^{-n} = \frac{1}{b^n}$.
Solving exponential equations: To solve equations with the variable in the exponent, logarithms are often used to isolate the variable.