Solve for x 4/7+3/x=(2x+1)/(7x)
The given problem is an algebraic equation where the variable x appears in both the numerator and denominator of fractions. The equation is set up as a proportion, involving a sum on one side and a single fraction on the other side. The task is to find the value of x that makes both sides of the equation equal. This typically involves finding a common denominator, combining like terms, and then isolating the variable x to solve for it.
$\frac{4}{7} + \frac{3}{x} = \frac{2 x + 1}{7 x}$
Isolate terms with $x$ on one side of the equation.
Subtract $\frac{4}{7}$ from both sides: $\frac{3}{x} = \frac{2x + 1}{7x} - \frac{4}{7}$
Simplify the equation.
Divide $\frac{2x + 1}{7x}$ into two parts: $\frac{3}{x} = \frac{2x}{7x} + \frac{1}{7x} - \frac{4}{7}$
Reduce fractions by canceling $x$.
Eliminate $x$ where possible: $\frac{3}{x} = \frac{2}{7} + \frac{1}{7x} - \frac{4}{7}$
Rewrite the equation: $\frac{3}{x} = \frac{2}{7} + \frac{1}{7x} - \frac{4}{7}$
Combine like terms over a common denominator: $\frac{3}{x} = \frac{2 - 4}{7} + \frac{1}{7x}$
Subtract $4$ from $2$: $\frac{3}{x} = \frac{-2}{7} + \frac{1}{7x}$
Place the negative sign in front: $\frac{3}{x} = -\frac{2}{7} + \frac{1}{7x}$
Determine the least common denominator (LCD) of the equation.
The LCD is the least common multiple (LCM) of the denominators: $x, 7, 7x$
To find the LCM, separate the process for numbers and variables: LCM of $1, 7, 7$ and LCM of $x^1, x^1$.
LCM is the smallest number divisible by all numbers: List prime factors and multiply the highest power of each.
The number $1$ is not prime.
Since $7$ is prime, it remains unchanged.
The LCM of $1, 7, 7$ is $7$.
The variable $x^1$ simplifies to $x$.
The LCM of $x^1, x^1$ is $x$.
Combine the numeric and variable parts for the LCD: $7x$
Eliminate fractions by multiplying each term by the LCD, $7x$.
Multiply the equation by $7x$: $\frac{3}{x}(7x) = -\frac{2}{7}(7x) + \frac{1}{7x}(7x)$
Simplify the left side.
Use the commutative property: $7\frac{3}{x}x = -\frac{2}{7}(7x) + \frac{1}{7x}(7x)$
Multiply $7$ and $\frac{3}{x}$: $\frac{21}{x}x = -\frac{2}{7}(7x) + \frac{1}{7x}(7x)$
Cancel $x$: $21 = -\frac{2}{7}(7x) + \frac{1}{7x}(7x)$
Simplify the right side.
Simplify each term.
Cancel $7$: $21 = -2x + \frac{1}{7x}(7x)$
Use the commutative property: $21 = -2x + 7\frac{1}{7x}x$
Cancel $7$: $21 = -2x + \frac{1}{x}x$
Cancel $x$: $21 = -2x + 1$
Solve for $x$.
Rearrange the equation: $-2x + 1 = 21$
Isolate $x$-terms.
Subtract $1$ from both sides: $-2x = 21 - 1$
Calculate the result: $-2x = 20$
Divide by $-2$ to solve for $x$.
Divide each term by $-2$: $\frac{-2x}{-2} = \frac{20}{-2}$
Simplify the left side: $x = \frac{20}{-2}$
Simplify the right side: $x = -10$
Isolating Variables: When solving for a variable, it's common to isolate terms containing the variable on one side of the equation.
Simplifying Fractions: Fractions can be simplified by canceling out common factors in the numerator and denominator.
Least Common Denominator (LCD): The LCD of several fractions is the least common multiple (LCM) of their denominators. It's used to combine fractions or eliminate them from an equation.
Prime Numbers: A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. Prime factorization helps in finding the LCM.
Commutative Property of Multiplication: This property states that the order in which two numbers are multiplied does not affect the product.
Solving Linear Equations: Linear equations are solved by performing operations that maintain the equality, such as adding, subtracting, multiplying, or dividing both sides by the same number.