Solve for x (5x-2)/(3x)=7
The problem presents an equation in which you are asked to solve for the variable x. The equation involves a fraction with the expression (5x-2) in the numerator and the variable x in the denominator, multiplied by the scalar 3. This entire expression is then set equal to the number 7, and the task is to manipulate the equation using algebraic methods to find the value of x that satisfies this equation.
$\frac{5 x - 2}{3 x} = 7$
Identify the LCD of all the fractions involved in the equation.
The LCD for the values $3x$ and $1$ is equivalent to finding the Least Common Multiple (LCM) of their denominators.
The LCM of $1$ and any other number or expression is simply that number or expression itself, which in this case is $3x$.
Eliminate the fractions by multiplying every term in the equation $\frac{5x - 2}{3x} = 7$ by $3x$.
Multiply both sides of the equation $\frac{5x - 2}{3x} = 7$ by $3x$ to clear the fractions.
Apply the commutative property of multiplication to rearrange the terms: $3x \cdot \frac{5x - 2}{3x} = 7 \cdot 3x$.
Factor out the $3$ from $3x$ in the fraction.
Cancel out the common factor of $3$ from the numerator and denominator.
After cancellation, the expression becomes $\frac{5x - 2}{x} \cdot x = 7 \cdot 3x$.
Cancel out the common factor of $x$ from the numerator and denominator.
The simplified expression is now $5x - 2 = 7 \cdot 3x$.
Multiply $7$ by $3x$ to get $21x$: $5x - 2 = 21x$.
Get all terms containing $x$ on one side of the equation.
Subtract $21x$ from both sides: $5x - 2 - 21x = 0$.
Combine the $x$ terms: $-16x - 2 = 0$.
Add $2$ to both sides to isolate the $x$ term: $-16x = 2$.
Divide both sides of the equation by $-16$: $\frac{-16x}{-16} = \frac{2}{-16}$.
Cancel the common factor of $-16$.
After cancellation, the left side becomes $x$.
The equation simplifies to $x = \frac{2}{-16}$.
Factor out the common factors of $2$ and $-16$.
After canceling the common factor, the fraction reduces to $x = \frac{1}{-8}$.
Place the negative sign in front of the fraction: $x = -\frac{1}{8}$.
The solution can be expressed as:
Exact Form: $x = -\frac{1}{8}$ Decimal Form: $x = -0.125$
The problem-solving process involves several key mathematical concepts:
Least Common Denominator (LCD): The smallest common multiple of the denominators of two or more fractions. It is used to combine fractions into a single fraction or to eliminate fractions from an equation.
Least Common Multiple (LCM): The smallest multiple that is exactly divisible by every number of a set. When dealing with fractions, the LCM of the denominators is used as the LCD.
Commutative Property of Multiplication: This property states that the order in which two numbers are multiplied does not change the product. For example, $ab = ba$.
Cancellation: A method used to simplify expressions by dividing both the numerator and the denominator by a common factor.
Combining Like Terms: A process used to simplify an expression or equation by adding or subtracting terms that have the same variables raised to the same power.
Isolating the Variable: The process of manipulating an equation to get the variable of interest, often represented as $x$, by itself on one side of the equation.
Simplifying Expressions: Reducing expressions to their simplest form by performing arithmetic operations and combining like terms.
Understanding these concepts is crucial for solving algebraic equations and simplifying mathematical expressions.