Simplify (p-q)/(p^3q^2)-(p+q)/(p^2q^3)
The problem presented is an algebraic expression that requires simplification. Specifically, you have two fractions with variables p and q in the numerators and denominators, and these fractions are being subtracted from one another. The first fraction has (p - q) as the numerator and p^3q^2 as the denominator, whereas the second fraction has (p + q) in the numerator and p^2q^3 in the denominator. The question is asking to simplify the expression by combining these two fractions into one simplified fraction, which likely involves finding a common denominator, performing the subtraction, and then simplifying the resultant expression by reducing any common factors in the numerator and the denominator.
$\frac{p - q}{p^{3} q^{2}} - \frac{p + q}{p^{2} q^{3}}$
To find a common denominator for $\frac{p - q}{p^3 q^2}$, multiply by $\frac{q}{q}$ to get $\frac{(p - q)q}{p^3 q^3} - \frac{p + q}{p^2 q^3}$.
For $\frac{p + q}{p^2 q^3}$ to have the same denominator, multiply by $\frac{p}{p}$ to obtain $\frac{(p - q)q}{p^3 q^3} - \frac{(p + q)p}{p^3 q^3}$.
Express both fractions with a common denominator of $p^3 q^3$ by multiplying each by an appropriate form of 1.
Multiply $\frac{p - q}{p^3 q^2}$ by $\frac{q}{q}$ to get $\frac{(p - q)q}{p^3 q^3} - \frac{p + q}{p^2 q^3} \cdot \frac{p}{p}$.
Raise $q$ to the power of 1 to maintain the same base.
Combine exponents using the power rule $a^m a^n = a^{m + n}$ to get $\frac{(p - q)q}{p^3 q^{1 + 2}} - \frac{p + q}{p^2 q^3} \cdot \frac{p}{p}$.
Add the exponents 1 and 2 to get $\frac{(p - q)q}{p^3 q^3} - \frac{p + q}{p^2 q^3} \cdot \frac{p}{p}$.
Multiply $\frac{p + q}{p^2 q^3}$ by $\frac{p}{p}$ to get $\frac{(p - q)q}{p^3 q^3} - \frac{(p + q)p}{p^3 q^3}$.
Raise $p$ to the power of 1.
Use the power rule to combine exponents and get $\frac{(p - q)q}{p^3 q^3} - \frac{(p + q)p}{p^{1 + 2} q^3}$.
Add the exponents 1 and 2 to get $\frac{(p - q)q}{p^3 q^3} - \frac{(p + q)p}{p^3 q^3}$.
Combine the numerators over the common denominator to obtain $\frac{(p - q)q - (p + q)p}{p^3 q^3}$.
Simplify the numerator.
Apply the distributive property to get $\frac{pq - q^2 - (p + q)p}{p^3 q^3}$.
Multiply $q$ by $q$.
Rearrange to $\frac{pq - q \cdot q - (p + q)p}{p^3 q^3}$.
Multiply $q$ by $q$ to get $\frac{pq - q^2 - (p + q)p}{p^3 q^3}$.
Apply the distributive property again.
Distribute to get $\frac{pq - q^2 - p \cdot p - qp}{p^3 q^3}$.
Multiply $p$ by $p$.
Rearrange to $\frac{pq - q^2 - p \cdot p - qp}{p^3 q^3}$.
Multiply $p$ by $p$ to get $\frac{pq - q^2 - p^2 - qp}{p^3 q^3}$.
Subtract $qp$ from $pq$.
Rearrange to $\frac{-q^2 - p^2 + pq - qp}{p^3 q^3}$.
Subtract $pq$ from $pq$ to get $\frac{-q^2 - p^2}{p^3 q^3}$.
Combine $-q^2 - p^2$ and $0$ to get $\frac{-q^2 - p^2}{p^3 q^3}$.
Factor out common terms.
Factor $-1$ out of $-q^2$ to get $\frac{-1(q^2) - p^2}{p^3 q^3}$.
Factor $-1$ out of $-p^2$ to obtain $\frac{-1(q^2) - 1(p^2)}{p^3 q^3}$.
Factor $-1$ out of the entire numerator to get $\frac{-1(q^2 + p^2)}{p^3 q^3}$.
Simplify the expression.
Rewrite as $-1(q^2 + p^2)$ to get $\frac{-1(q^2 + p^2)}{p^3 q^3}$.
Move the negative in front of the fraction to get $-\frac{q^2 + p^2}{p^3 q^3}$.
Common Denominator: To combine fractions, they must have the same denominator. This often involves multiplying by a form of 1 (e.g., $\frac{p}{p}$ or $\frac{q}{q}$) to achieve a common denominator without changing the value of the fractions.
Power Rule: When multiplying like bases, the exponents are added together (e.g., $a^m \cdot a^n = a^{m+n}$).
Distributive Property: This property allows us to multiply a single term by each term within a parenthesis (e.g., $a(b + c) = ab + ac$).
Simplifying Expressions: Involves combining like terms, factoring out common factors, and reducing fractions to their simplest form.
Negative Exponents and Factoring: Factoring out a negative can help simplify expressions, especially when dealing with subtraction in numerators or denominators.