Evaluate ( square root of 3/2)^2
The question provided asks for the evaluation of the squared expression of the square root of 3/2. Put simply, it's requesting to calculate what you get when you take the square root of three-halves and then square the result. The operation should undo the square root since squaring is the inverse of taking a square root.
$\left(\left(\right. \sqrt{\frac{3}{2}} \left.\right)\right)^{2}$
Express $\sqrt{\frac{3}{2}}$ as $\frac{\sqrt{3}}{\sqrt{2}}$ and then square it: $\left(\frac{\sqrt{3}}{\sqrt{2}}\right)^2$.
Rationalize the denominator by multiplying $\frac{\sqrt{3}}{\sqrt{2}}$ with $\frac{\sqrt{2}}{\sqrt{2}}$: $\left(\frac{\sqrt{3}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}\right)^2$.
Simplify the denominator step by step.
Multiply the numerators and denominators: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{\sqrt{2} \cdot \sqrt{2}}\right)^2$.
Express $\sqrt{2}$ as a power of 2: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{(2^{\frac{1}{2}})^1 \cdot \sqrt{2}}\right)^2$.
Apply the power rule for exponents: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{(2^{\frac{1}{2}})^1 \cdot (2^{\frac{1}{2}})^1}\right)^2$.
Combine the exponents using the rule $a^{m} \cdot a^{n} = a^{m + n}$: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{(2^{\frac{1}{2}})^{1 + 1}}\right)^2$.
Add the exponents: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{(2^{\frac{1}{2}})^2}\right)^2$.
Rewrite $(2^{\frac{1}{2}})^2$ as 2.
Represent $\sqrt{2}$ as $2^{\frac{1}{2}}$: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{(2^{\frac{1}{2}})^2}\right)^2$.
Apply the power rule $(a^m)^n = a^{mn}$: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{2^{\frac{1}{2} \cdot 2}}\right)^2$.
Multiply the exponents: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{2^{\frac{2}{2}}}\right)^2$.
Simplify the exponent: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{2^1}\right)^2$.
Square the fraction: $\left(\frac{\sqrt{3} \cdot \sqrt{2}}{2}\right)^2$.
Combine the radicals in the numerator: $\left(\frac{\sqrt{3 \cdot 2}}{2}\right)^2$.
Simplify the expression further.
Square the numerator and denominator separately: $\frac{(\sqrt{6})^2}{2^2}$.
Rewrite $(\sqrt{6})^2$ as 6.
Express $\sqrt{6}$ as $6^{\frac{1}{2}}$: $\frac{(6^{\frac{1}{2}})^2}{2^2}$.
Apply the power rule $(a^m)^n = a^{mn}$: $\frac{6^{\frac{1}{2} \cdot 2}}{2^2}$.
Simplify the exponent: $\frac{6^{\frac{2}{2}}}{2^2}$.
Reduce the fraction: $\frac{6^1}{2^2}$.
Evaluate the exponent: $\frac{6}{2^2}$.
Square the denominator: $\frac{6}{4}$.
Reduce the fraction by canceling common factors.
Factor out a 2 from 6: $\frac{2 \cdot 3}{4}$.
Cancel the common factors.
Factor out a 2 from 4: $\frac{2 \cdot 3}{2 \cdot 2}$.
Cancel the 2s: $\frac{\cancel{2} \cdot 3}{\cancel{2} \cdot 2}$.
Rewrite the simplified fraction: $\frac{3}{2}$.
Present the final result in various forms.
Exact Form: $\frac{3}{2}$ Decimal Form: $1.5$ Mixed Number Form: $1 \frac{1}{2}$
The problem involves evaluating the square of a square root, which is a common operation in algebra. The steps taken to solve this problem include:
Rationalizing the Denominator: This is the process of eliminating radicals from the denominator of a fraction. In this case, we multiply by a fraction equivalent to 1 that contains the radical in both the numerator and denominator.
Simplifying Radicals: When radicals (square roots) are multiplied or divided, they can often be combined or simplified using the properties of exponents.
Properties of Exponents: The power rule $(a^m)^n = a^{mn}$ and the product rule $a^m \cdot a^n = a^{m+n}$ are used to simplify expressions involving exponents.
Squaring a Fraction: When squaring a fraction, both the numerator and the denominator are squared separately.
Reducing Fractions: Common factors in the numerator and denominator can be canceled to simplify the fraction.
Alternative Forms: The final result can be expressed in different forms, such as an exact fraction, a decimal, or a mixed number, depending on the context or preference.