Problem

Simplify square root of 2( square root of 8+4 square root of 3)

The question is asking for the simplification of a nested radical expression. Specifically, it involves the square root of 2 multiplied by the sum of another square root, which is the square root of 8, and four times the square root of 3. To simplify this expression, one would typically use properties of radicals and basic arithmetic to combine and reduce the terms inside and outside the square roots to their simplest form. The goal is to express the result with as few radicals as possible and ideally with no radicals left within the square root.

$\sqrt{2} \left(\right. \sqrt{8} + 4 \sqrt{3} \left.\right)$

Answer

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Solution:

Step:1

Break down each term within the expression.

Step:1.1

Express $8$ as a product of $2^2$ and $2$.

Step:1.1.1

Extract $4$ as a common factor from $8$. $\sqrt{2} \left( \sqrt{4 \cdot 2} + 4 \sqrt{3} \right)$

Step:1.1.2

Represent $4$ as $2^2$. $\sqrt{2} \left( \sqrt{2^2 \cdot 2} + 4 \sqrt{3} \right)$

Step:1.2

Extract terms from under the square root. $\sqrt{2} \left( 2 \sqrt{2} + 4 \sqrt{3} \right)$

Step:2

Use the distributive law to expand. $\sqrt{2} \cdot 2 \sqrt{2} + \sqrt{2} \cdot 4 \sqrt{3}$

Step:3

Calculate $\sqrt{2} \cdot 2 \sqrt{2}$.

Step:3.1

Elevate $\sqrt{2}$ to the power of $1$. $2 \left( \left(\sqrt{2}\right)^1 \sqrt{2} \right) + \sqrt{2} \cdot 4 \sqrt{3}$

Step:3.2

Apply the exponent of $1$ to $\sqrt{2}$. $2 \left( \left(\sqrt{2}\right)^1 \left(\sqrt{2}\right)^1 \right) + \sqrt{2} \cdot 4 \sqrt{3}$

Step:3.3

Utilize the rule $a^{m} a^{n} = a^{m + n}$ to combine the powers. $2 \left(\sqrt{2}\right)^{1 + 1} + \sqrt{2} \cdot 4 \sqrt{3}$

Step:3.4

Sum the exponents $1$ and $1$. $2 \left(\sqrt{2}\right)^2 + \sqrt{2} \cdot 4 \sqrt{3}$

Step:4

Compute $\sqrt{2} \cdot 4 \sqrt{3}$.

Step:4.1

Merge using the radical product rule. $2 \left(\sqrt{2}\right)^2 + 4 \sqrt{2 \cdot 3}$

Step:4.2

Multiply $2$ and $3$. $2 \left(\sqrt{2}\right)^2 + 4 \sqrt{6}$

Step:5

Simplify each component.

Step:5.1

Convert $\left(\sqrt{2}\right)^2$ back to $2$.

Step:5.1.1

Rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$. $2 \left(2^{\frac{1}{2}}\right)^2 + 4 \sqrt{6}$

Step:5.1.2

Apply the rule $\left(a^{m}\right)^{n} = a^{m \cdot n}$. $2 \cdot 2^{\frac{1}{2} \cdot 2} + 4 \sqrt{6}$

Step:5.1.3

Multiply $\frac{1}{2}$ by $2$. $2 \cdot 2^{\frac{2}{2}} + 4 \sqrt{6}$

Step:5.1.4

Simplify the fraction.

Step:5.1.4.1

Reduce the common factors. $2 \cdot 2^{\frac{\cancel{2}}{\cancel{2}}} + 4 \sqrt{6}$

Step:5.1.4.2

Express the simplified power. $2 \cdot 2^1 + 4 \sqrt{6}$

Step:5.1.5

Compute the power of $2$. $2 \cdot 2 + 4 \sqrt{6}$

Step:5.2

Multiply $2$ by $2$. $4 + 4 \sqrt{6}$

Step:6

Present the final result in various forms.

Exact Form: $4 + 4 \sqrt{6}$ Decimal Form: $13.79795897 \ldots$

Knowledge Notes:

The problem involves simplifying a nested radical expression. The key knowledge points used in the solution include:

  1. Radicals: Understanding how to simplify square roots and the properties of radicals is essential. For instance, $\sqrt{a^2} = a$ when $a$ is non-negative.

  2. Exponent Rules: Familiarity with exponent rules, such as $a^{m} a^{n} = a^{m + n}$ and $\left(a^{m}\right)^{n} = a^{m \cdot n}$, is crucial for simplifying expressions involving powers.

  3. Distributive Property: This property allows us to multiply a single term by each term within a parenthesis, which is used in Step 2.

  4. Combining Like Terms: When simplifying expressions, like terms can be combined to form a simpler expression.

  5. Product Rule for Radicals: This rule states that $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$, which is used to combine square roots in Step 4.

  6. Simplifying Expressions: The process of reducing expressions to their simplest form by performing arithmetic operations and applying algebraic rules.

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