Problem

Simplify square root of square root of 243(x+1)

The given problem is asking you to perform two consecutive square root operations on the expression 243(x+1). You are first supposed to simplify by finding the square root of the quantity 243(x+1)and then subsequently find the square root of the resulting expression. The entire operation should be simplified to its most basic form if possible.

243(x+1)

Answer

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Solution:

Step 1:

Express 243(x+1) as (32)23(x+1).

Step 1.1:

Extract 81 from 243 to get 813(x+1).

Step 1.2:

Represent 81 as 92 to obtain 923(x+1).

Step 1.3:

Convert 9 to 32 resulting in (32)23(x+1).

Step 1.4:

Introduce additional parentheses to clarify the expression ((32)2)(3(x+1)).

Step 2:

Extract terms from under the radical sign to get 323(x+1).

Step 3:

Calculate 32 to simplify to 93(x+1).

Step 4:

Rewrite 93(x+1) as 323(x+12).

Step 4.1:

Represent 9 as 32 to get 323(x+1).

Step 4.2:

Express 1 as 12 to arrive at 323(x+12).

Step 5:

Remove terms from under the radical to have 33(x+12).

Step 6:

Recognize that any number to the power of one remains unchanged to simplify to 33(x+1).

Step 7:

Rewrite the nested radical 3(x+1) as the fourth root to get 33(x+1)4.

Knowledge Notes:

  1. Simplifying nested radicals: When simplifying expressions like a, we can rewrite them as a4 because the square root of a square root is equivalent to the fourth root.

  2. Exponent rules: Remember that (ab)c=abc and abac=ab+c. These rules are used to simplify expressions with exponents.

  3. Square roots and radicals: The square root of a product can be expressed as the product of the square roots, i.e., ab=ab.

  4. Simplifying expressions: When simplifying expressions, it's often helpful to factor out perfect squares or cubes to make the radical simpler.

  5. Rationalizing the denominator (not applicable in this problem, but a common technique in simplifying radicals): If a radical is in the denominator, we can multiply the numerator and the denominator by a suitable term to remove the radical from the denominator.

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