Simplify 0.5/(4+3i)
The question is asking you to perform the mathematical operation of simplification on a complex fraction. The fraction given is 0.5 divided by the sum of a real number, which is 4, and an imaginary number, which is indicated by the use of 'i' (representing the square root of -1). You are expected to simplify this expression to find the simplest form of the complex number that expresses the same value.
$\frac{0.5}{4 + 3 i}$
Multiply both the numerator and denominator by the conjugate of the denominator:
$$\frac{0.5}{4 + 3i} \cdot \frac{4 - 3i}{4 - 3i}$$
$$\frac{0.5(4 - 3i)}{(4 + 3i)(4 - 3i)}$$
$$\frac{0.5 \cdot 4 + 0.5(-3i)}{(4 + 3i)(4 - 3i)}$$
$$\frac{2 - 1.5i}{(4 + 3i)(4 - 3i)}$$
$$\frac{2 - 1.5i}{4(4 - 3i) + 3i(4 - 3i)}$$
$$\frac{2 - 1.5i}{16 - 12i + 12i - 9i^2}$$
Replace $i^2$ with $-1$ and add the terms:
$$\frac{2 - 1.5i}{25}$$
Divide the real and imaginary parts:
$$\frac{2}{25} - \frac{1.5i}{25}$$
$$\frac{2}{25}$$
$$- \frac{1.5i}{25}$$
$$\frac{2}{25} - 0.06i$$
To simplify a complex fraction, we often multiply by the conjugate of the denominator to eliminate the imaginary part from the denominator. The conjugate of a complex number $a + bi$ is $a - bi$. When we multiply a complex number by its conjugate, the result is a real number because $(a + bi)(a - bi) = a^2 - (bi)^2 = a^2 - b^2i^2$, and since $i^2 = -1$, this simplifies to $a^2 + b^2$.
In this problem, we used the distributive property, which states that $a(b + c) = ab + ac$, to expand the numerator and the denominator. We also used the fact that $i^2 = -1$ to simplify the denominator after expansion.
After simplifying the denominator to a real number, we split the fraction into real and imaginary parts and simplified each part separately. The final step was to combine these parts to express the simplified form of the original complex fraction.