Problem

Simplify ( square root of 28y^5)/( square root of 7y)

The problem is asking for the simplification of an algebraic expression that involves square roots. Specifically, you are expected to simplify the expression by dividing the square root of (28y^5) by the square root of (7y). This requires knowledge of the properties of square roots and the rules for simplifying expressions with exponents.

$\frac{\sqrt{28 y^{5}}}{\sqrt{7} y}$

Answer

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Solution:

Step 1:

Merge $\sqrt{28 y^{5}}$ and $\sqrt{7y}$ into a single square root expression. $\frac{\sqrt{28 y^{5} / 7y}}{1}$

Step 2:

Simplify the fraction inside the radical.

Step 2.1:

Extract the factor of 7 from $28 y^{5}$. $\frac{\sqrt{7 \cdot 4 y^{5} / 7}}{1}$

Step 2.2:

Eliminate the common factors.

Step 2.2.1:

Separate the factor of 7 from the denominator. $\frac{\sqrt{7 \cdot 4 y^{5} / (7 \cdot 1)}}{1}$

Step 2.2.2:

Remove the common factor of 7. $\frac{\sqrt{\cancel{7} \cdot 4 y^{5} / \cancel{7} \cdot 1}}{1}$

Step 2.2.3:

Reformulate the expression. $\frac{\sqrt{4 y^{5}}}{1}$

Step 2.2.4:

Divide $4 y^{5}$ by 1. $\sqrt{4 y^{5}}$

Step 3:

Refine the numerator's radical.

Step 3.1:

Express $4 y^{5}$ as $(2 y^{2})^{2} \cdot y$.

Step 3.1.1:

Represent 4 as $2^{2}$. $\frac{\sqrt{2^{2} \cdot y^{5}}}{1}$

Step 3.1.2:

Factor $y^{4}$ from the expression. $\frac{\sqrt{2^{2} \cdot (y^{4} \cdot y)}}{1}$

Step 3.1.3:

Rewrite $y^{4}$ as $(y^{2})^{2}$. $\frac{\sqrt{2^{2} \cdot ((y^{2})^{2} \cdot y)}}{1}$

Step 3.1.4:

Rephrase $2^{2} \cdot (y^{2})^{2}$ as $(2 y^{2})^{2}$. $\sqrt{(2 y^{2})^{2} \cdot y}$

Step 3.2:

Extract terms from under the square root. $2 y^{2} \sqrt{y}$

Step 4:

Reduce the common $y$ terms.

Step 4.1:

Factor out $y$ from $2 y^{2} \sqrt{y}$. $\frac{y \cdot (2 y \sqrt{y})}{y}$

Step 4.2:

Eliminate the common factors.

Step 4.2.1:

Raise $y$ to the first power. $\frac{y \cdot (2 y \sqrt{y})}{y^{1}}$

Step 4.2.2:

Separate $y$ from $y^{1}$. $\frac{y \cdot (2 y \sqrt{y})}{y \cdot 1}$

Step 4.2.3:

Remove the common $y$ factor. $\frac{\cancel{y} \cdot (2 y \sqrt{y})}{\cancel{y} \cdot 1}$

Step 4.2.4:

Reformulate the expression. $\frac{2 y \sqrt{y}}{1}$

Step 4.2.5:

Divide $2 y \sqrt{y}$ by 1. $2 y \sqrt{y}$

Knowledge Notes:

The problem involves simplifying a radical expression, which requires understanding of square roots, factoring, and simplifying fractions. Here are the relevant knowledge points:

  1. Square Roots: The square root of a number is a value that, when multiplied by itself, gives the original number. For example, $\sqrt{9} = 3$ because $3 \times 3 = 9$.

  2. Radicals: A radical expression is an expression that includes a root, such as a square root, cube root, etc. Simplifying radicals involves factoring numbers or expressions and pulling out pairs of numbers or variables.

  3. Factoring: Factoring is the process of breaking down a number or expression into its component factors. For example, $28 = 7 \times 4$.

  4. Simplifying Fractions: To simplify a fraction, divide the numerator and the denominator by their greatest common factor.

  5. Algebraic Manipulation: This involves rewriting expressions in different but equivalent forms to simplify them or make them more understandable. This can include expanding, factoring, and canceling common factors.

  6. Properties of Exponents: When simplifying expressions involving exponents, remember that $(a^m)^n = a^{mn}$ and $a^m \cdot a^n = a^{m+n}$.

  7. Combining Radicals: When dealing with square roots, you can combine them under one radical if they are being multiplied or divided. For example, $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ and $\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$.

By applying these principles, one can simplify complex radical expressions step by step.

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