Simplify 26÷negitive*13
The question asks for the simplification of the division of two numbers: 26 (the dividend) and -13 (the divisor). The operation involved here is division, and it appears that there's a typographical error with the word "negative," which should be "negative". The question is essentially requesting the result of dividing 26 by negative 13.
$26 \div n e g i t i v e \cdot 13$
Step 1.1: Apply the exponential function to the denominator. $26 \div \text{negative} \left( e^{1} \right) \times 13$
Step 1.2: Repeat the application of the exponential function. $26 \div \text{negative} \left( e^{1} \times e^{1} \right) \times 13$
Step 1.3: Utilize the exponentiation rule $a^{m} \times a^{n} = a^{m + n}$. $26 \div \text{negative} e^{1 + 1} \times 13$
Step 1.4: Perform the addition of the exponents. $26 \div \text{negative} e^{2} \times 13$
Step 1.5: Combine the imaginary units by adding their exponents.
The problem-solving process involves simplifying an expression that contains a division by a negative exponentiated value. The steps include manipulating the expression using properties of exponents and imaginary numbers. Here are the relevant knowledge points:
Exponentiation: Raising a number to a power, such as $e^{1}$, where $e$ is the base of the natural logarithm.
Power Rule: A rule for simplifying expressions with exponents, stating that $a^{m} \times a^{n} = a^{m + n}$.
Imaginary Unit: The imaginary unit $i$ is defined as $\sqrt{-1}$, and $i^{2} = -1$.
Negative Numbers: A negative number times another negative number results in a positive number.
Fraction Representation: Division can be represented as a fraction, where the numerator is the dividend and the denominator is the divisor.
Combining Terms: Multiplication and division operations are performed to combine terms into a simpler form.
Negative Sign Placement: A negative sign can be moved in front of a fraction to indicate that the entire fraction is negative.
The solution involves using these principles to simplify the given expression step by step, ensuring that the negative signs and imaginary units are handled correctly to arrive at the final simplified result.