Simplify ( cube root of -7x^6y^4)/( cube root of 448y^3)
The problem provided is asking for the simplification of a mathematical expression involving cube roots. Specifically, the task is to simplify the expression by taking the cube root of a fraction. The numerator of the fraction is the cube root of the product of -7, x to the power of 6, and y to the power of 4. The denominator is the cube root of the product of 448 and y to the power of 3. The goal is to perform the cube root operation on both the numerator and the denominator and then simplify the expression to its simplest form. This may involve canceling out common factors in the numerator and denominator and reducing the expression to lowest terms.
$\frac{\sqrt[3]{- 7 x^{6} y^{4}}}{\sqrt[3]{448 y^{3}}}$
Merge the cube roots $\sqrt[3]{-7x^6y^4}$ and $\sqrt[3]{448y^3}$ into a single cube root expression: $\sqrt[3]{\frac{-7x^6y^4}{448y^3}}$.
Simplify the fraction within the cube root by eliminating common factors.
Extract the factor of $7$ from the numerator: $\sqrt[3]{\frac{7(-x^6y^4)}{448y^3}}$.
Extract the factor of $7$ from the denominator: $\sqrt[3]{\frac{7(-x^6y^4)}{7(64y^3)}}$.
Eliminate the common factor of $7$: $\sqrt[3]{\frac{\cancel{7}(-x^6y^4)}{\cancel{7}(64y^3)}}$.
Reformulate the expression: $\sqrt[3]{\frac{-x^6y^4}{64y^3}}$.
Further reduce the expression by canceling out common $y$ terms.
Factor out $y^3$ from the numerator: $\sqrt[3]{\frac{y^3(-x^6y)}{64y^3}}$.
Proceed to cancel the common $y^3$ factors.
Factor $y^3$ from the denominator: $\sqrt[3]{\frac{y^3(-x^6y)}{y^3 \cdot 64}}$.
Cancel out the common $y^3$ factor: $\sqrt[3]{\frac{\cancel{y^3}(-x^6y)}{\cancel{y^3} \cdot 64}}$.
Rephrase the simplified expression: $\sqrt[3]{\frac{-x^6y}{64}}$.
Position the negative sign in front of the cube root: $\sqrt[3]{-\frac{x^6y}{64}}$.
Express $-\frac{x^6y}{64}$ as $((-1)^3)(\frac{x^2}{4})^3y$.
Represent $-1$ as $(-1)^3$: $\sqrt[3]{(-1)^3\frac{x^6y}{64}}$.
Extract the cube of $x^2$ from $x^6y$: $\sqrt[3]{(-1)^3\frac{(x^2)^3y}{64}}$.
Extract the cube of $4$ from $64$: $\sqrt[3]{(-1)^3\frac{(x^2)^3y}{4^3 \cdot 1}}$.
Rearrange the fraction $\frac{(x^2)^3y}{4^3 \cdot 1}$: $\sqrt[3]{(-1)^3((\frac{x^2}{4})^3y)}$.
Combine $(-1)^3$ and $(\frac{x^2}{4})^3$ into a single term: $\sqrt[3]{(-\frac{x^2}{4})^3y}$.
Extract terms from under the cube root: $-\frac{x^2}{4}\sqrt[3]{y}$.
Combine the cube root of $y$ with the fraction $\frac{x^2}{4}$: $-\frac{\sqrt[3]{y}x^2}{4}$.
The problem-solving process involves simplifying a cube root expression. The steps taken include combining cube roots, factoring out common terms, canceling common factors, and extracting terms from under the cube root. The process requires knowledge of the properties of radicals, factoring, and simplifying algebraic expressions.
Relevant knowledge points include:
Cube root simplification: $\sqrt[3]{a^3} = a$.
Factoring: Finding common factors in the numerator and denominator to simplify fractions.
Properties of exponents: $(a^m)^n = a^{mn}$ and $a^m \cdot a^n = a^{m+n}$.
Negative exponents and radicals: $(-a)^n = a^n$ if $n$ is even, and $(-a)^n = -a^n$ if $n$ is odd.
Simplifying expressions: Combining like terms and reducing fractions to their simplest form.