Simplify 9 square root of 32x^12y^12
In the given problem, you are asked to perform a mathematical simplification on the expression "9 square root of 32x^12y^12." The problem involves algebraic and radical simplification. The expression contains a numerical coefficient (9), a square root sign, and a radicand that consists of a constant (32) multiplied by variables with exponents (x^12 and y^12). You are expected to simplify this expression by following the rules for simplifying square roots and exponents, and by possibly factoring out perfect squares from under the square root to reduce the expression to its simplest form.
$9 \sqrt{32 x^{12} y^{12}}$
Express $32x^{12}y^{12}$ as $(4x^6y^6)^2 \cdot 2$.
Identify the perfect square factor in $32$, which is $16$. Thus, we have $9\sqrt{16 \cdot 2x^{12}y^{12}}$.
Recognize that $16$ is the square of $4$, so write it as $9\sqrt{4^2 \cdot 2x^{12}y^{12}}$.
Notice that $x^{12}$ is a perfect square and can be written as $(x^6)^2$. Now we have $9\sqrt{4^2 \cdot 2(x^6)^2y^{12}}$.
Similarly, $y^{12}$ is a perfect square and can be written as $(y^6)^2$. The expression becomes $9\sqrt{4^2 \cdot 2(x^6)^2(y^6)^2}$.
Reorder the terms under the square root to group the perfect squares together: $9\sqrt{4^2(x^6)^2(y^6)^2 \cdot 2}$.
Combine the perfect squares into a single term: $9\sqrt{(4x^6y^6)^2 \cdot 2}$.
Extract the perfect square from under the radical: $9(4x^6y^6)\sqrt{2}$.
Multiply the coefficient $9$ by the extracted term $4$: $36x^6y^6\sqrt{2}$.
The problem involves simplifying a radical expression with a numerical coefficient. The key steps in simplifying such expressions include:
Identifying and factoring out perfect squares from the expression under the radical.
Using the property that $\sqrt{a^2} = a$ to simplify the expression, where $a$ is a non-negative real number.
Rearranging terms to group perfect squares together, which makes it easier to extract them from under the square root.
Multiplying the extracted terms by any coefficients outside the radical to obtain the final simplified expression.
In this problem, we used the fact that $32 = 16 \cdot 2$ and $16$ is a perfect square, $16 = 4^2$. We also used the property that any even power of a variable can be expressed as a square, for example, $x^{12} = (x^6)^2$ and $y^{12} = (y^6)^2$. By recognizing these perfect squares, we were able to simplify the radical expression.