Simplify square root of ((0.487x-35.999)^2)/(6-2)
The problem presented requires simplification of the square root of a rational expression. Specifically, it involves finding the square root of the square of a linear binomial divided by an integer subtraction. The binomial (0.487x-35.999) is squared, and this result is then divided by the result of the subtraction of two integers (6-2). The question is asking to simplify this expression as much as possible, potentially utilizing algebraic rules such as the square root of a square and properties of square roots over division.
$\sqrt{\frac{\left(\left(\right. 0.487 x - 35.999 \left.\right)\right)^{2}}{6 - 2}}$
Extract the factor $0.001$ from $0.487x - 35.999$.
Extract $0.001$ from $0.487x$: $\sqrt{\frac{(\left(0.001 \cdot 487x\right) - 35.999)^2}{6 - 2}}$
Extract $0.001$ from $-35.999$: $\sqrt{\frac{(\left(0.001 \cdot 487x\right) + \left(0.001 \cdot -35999\right))^2}{6 - 2}}$
Combine the factored expressions: $\sqrt{\frac{(\left(0.001 \cdot (487x - 35999)\right))^2}{6 - 2}}$
Square the factor $0.001$: $\sqrt{\frac{(0.001^2 \cdot (487x - 35999)^2)}{6 - 2}}$
Subtract $2$ from $6$: $\sqrt{\frac{(0.001^2 \cdot (487x - 35999)^2)}{4}}$
Square $0.001$: $\sqrt{\frac{0.000001 \cdot (487x - 35999)^2}{4}}$
Extract $0.000001$ from the squared term: $\sqrt{\frac{0.000001 \cdot ((487x - 35999)^2)}{4}}$
Factor $4$ from the denominator: $\sqrt{\frac{0.000001 \cdot ((487x - 35999)^2)}{4 \cdot 1}}$
Separate the fraction into two parts: $\sqrt{\frac{0.000001}{4} \cdot \frac{(487x - 35999)^2}{1}}$
Divide $0.000001$ by $4$: $\sqrt{0.00000025 \cdot \frac{(487x - 35999)^2}{1}}$
Factor $0.00000025$ from the numerator: $\sqrt{0.00000025 \cdot \frac{(487x - 35999)^2}{0.00000025 \cdot 4000000}}$
Cancel out $0.00000025$: $\sqrt{\frac{(487x - 35999)^2}{4000000}}$
Rewrite the expression without the canceled factor: $\sqrt{\frac{(487x - 35999)^2}{4000000}}$
Rewrite $4000000$ as $(2000)^2$: $\sqrt{\frac{(487x - 35999)^2}{(2000)^2}}$
Combine the terms under the radical: $\sqrt{\left(\frac{487x - 35999}{2000}\right)^2}$
Simplify the radical assuming positive real numbers: $\frac{487x - 35999}{2000}$
The problem involves simplifying a square root of a fraction where the numerator is a squared term and the denominator is a simple subtraction. The steps taken to simplify the expression involve factoring out common terms, applying the square of a product rule, simplifying the denominator, separating fractions, and canceling common factors.
Relevant knowledge points include:
Factoring: The process of breaking down an expression into its constituent factors.
Square of a product rule: $(ab)^2 = a^2b^2$, which is used to simplify the square of a product of two terms.
Simplifying fractions: The process of reducing the numerator and denominator to their simplest form by canceling common factors.
Square roots: The operation of finding a number which, when multiplied by itself, gives the original number. When a square root is applied to a squared expression, it simplifies to the base of the square, provided that the base represents a positive real number.
In this problem, the square root and the squared term cancel each other out, leaving a simplified fraction. The final result is obtained by recognizing that the square root of a square cancels out, assuming we are dealing with positive real numbers.