Problem

Simplify square root of 10^5

The question is asking for the process of simplifying the square root of an exponential number, in this case, the number is 10 raised to the power of 5. To simplify such an expression, one typically looks for ways to express the exponent in terms of a product of numbers, one of which is a square or another even number that can be easily rooted. They may also apply properties of exponents and radicals to simplify the expression to the most reduced form possible.

$\sqrt{\left(10\right)^{5}}$

Answer

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Solution:

Step 1:

Calculate $10^5$ to find the number under the square root: $\sqrt{10^5}$.

Step 2:

Express $10^5$ as a product of a perfect square and another term: $10^5 = (10^2)^2 \cdot 10$.

Step 2.1:

Isolate the perfect square part from the expression: $\sqrt{(10^2)^2 \cdot 10}$.

Step 2.2:

Recognize that $(10^2)^2$ is a perfect square: $\sqrt{(10^2)^2 \cdot 10}$.

Step 3:

Extract the square root of the perfect square outside the radical: $10^2 \sqrt{10}$.

Step 4:

Present the simplified result in its various forms:

  • Exact Form: $10^2 \sqrt{10}$
  • Decimal Form: Approximately $316.22776601 \ldots$

Knowledge Notes:

To simplify the square root of $10^5$, we use the following knowledge points:

  1. Exponentiation: Raising a number to a power, such as $10^5$, means multiplying the number by itself the specified number of times.

  2. Square Roots: The square root of a number is a value that, when multiplied by itself, gives the original number. For example, $\sqrt{100}$ is $10$ because $10 \times 10 = 100$.

  3. Perfect Squares: These are numbers that are squares of integers. For example, $100$ is a perfect square because it is $10^2$.

  4. Simplifying Square Roots: To simplify a square root, one can factor the number under the radical into a product of a perfect square and another term. The square root of the perfect square can be taken out of the radical, simplifying the expression.

  5. Radical Properties: The square root of a product can be expressed as the product of the square roots, i.e., $\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}$, provided that $a$ and $b$ are non-negative.

Using these principles, we can simplify $\sqrt{10^5}$ by expressing it as $\sqrt{(10^2)^2 \cdot 10}$, then taking the square root of the perfect square $(10^2)^2$ out of the radical, which is $10^2$, and leaving the square root of $10$ inside the radical. This results in $10^2 \sqrt{10}$, which can also be expressed in decimal form.

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