Simplify (4-x)/(x^2+3x-28)
The question given, "Simplify (4-x)/(x^2+3x-28)," is a problem involving the simplification of a rational expression. The numerator of the expression is "4 - x," and the denominator is a quadratic expression "x^2 + 3x - 28." The task is to simplify this expression by factoring the quadratic polynomial in the denominator and then reducing the fraction to its simplest form by canceling out any common factors that appear in both the numerator and the denominator.
$\frac{4 - x}{x^{2} + 3 x - 28}$
Identify two numbers that multiply to give $ac$ (the product of the coefficient of $x^2$ and the constant term) and add up to $b$ (the coefficient of $x$). For the quadratic $x^2 + 3x - 28$, we need numbers that multiply to $-28$ and add to $3$. The numbers are $-4$ and $7$.
The factored form of the denominator is $(x - 4)(x + 7)$, so the expression becomes $\frac{4 - x}{(x - 4)(x + 7)}$.
Notice that $4 - x$ is the negative of $x - 4$.
Rewrite the numerator as $-(-4) - x$ to make the common factor more apparent.
Factor $-1$ from the numerator to get $-(-4 + x)$.
The numerator simplifies to $-(x - 4)$.
The numerator is now the same as the denominator term $x - 4$, but with a negative sign.
The term $x - 4$ cancels out from the numerator and denominator, leaving $-\frac{1}{x + 7}$.
The simplified expression is $-\frac{1}{x + 7}$.
Place the negative sign in front of the fraction to get the final answer: $-\frac{1}{x + 7}$.
The AC method is a technique used to factor quadratic expressions of the form $ax^2 + bx + c$. It involves finding two numbers that multiply to $ac$ and add to $b$. Once these numbers are found, the quadratic can be factored into two binomials.
When simplifying rational expressions, it is important to look for common factors in the numerator and denominator that can be canceled. Remember that $a - b$ is the same as $-(b - a)$, which is a useful property when identifying common factors.
The final step in simplifying is to ensure that the expression is in its simplest form, with no common factors remaining other than 1, and the negative sign properly placed.