Integrate Using u-Substitution integral of (x^3)/(5-1/2x^4) with respect to x
The problem asks for the integration of a rational function where the integration method to be used is the u-substitution. Specifically, it is to integrate the expression (x^3)/(5 - (1/2)x^4) with respect to x. The u-substitution is a technique that simplifies the integration process by changing the variable of integration and the integrand to a simpler form that is easier to handle. You would typically look for a function within the integral that when differentiated, resembles another part of the integrand, which after substitution makes the integral simpler to evaluate. In this particular question, the student must identify the appropriate substitution that would simplify the integration process and then carry out the integration with respect to the new variable.
$\int \frac{x^{3}}{5 - \frac{1}{2} x^{4}} d x$
Assign $u = 5 - \frac{1}{2} x^{4}$. Compute the differential $du$.
Set $u = 5 - \frac{1}{2} x^{4}$ and differentiate with respect to $x$ to find $du$.
Take the derivative of $5 - \frac{1}{2} x^{4}$ with respect to $x$: $\frac{d}{d x} [5 - \frac{1}{2} x^{4}]$.
Perform the differentiation.
Apply the Sum Rule to find the derivative of $5 - \frac{1}{2} x^{4}$: $\frac{d}{d x} [5] + \frac{d}{d x} [- \frac{1}{2} x^{4}]$.
The derivative of a constant is zero: $0 + \frac{d}{d x} [- \frac{1}{2} x^{4}]$.
Calculate the derivative $\frac{d}{d x} [- \frac{1}{2} x^{4}]$.
Using the constant multiple rule, the derivative of $- \frac{1}{2} x^{4}$ is $- \frac{1}{2} \cdot \frac{d}{d x} [x^{4}]$.
Apply the Power Rule, which states that $\frac{d}{d x} [x^{n}] = n x^{n - 1}$ for $n = 4$: $- \frac{1}{2} \cdot (4 x^{3})$.
Simplify the constant multiplication: $- 2 \cdot (\frac{1}{2} x^{3})$.
Combine the constants: $- 2 \cdot \frac{1}{2} x^{3}$.
Simplify the expression: $- 2 \cdot \frac{1}{2} x^{3}$.
Simplify by canceling common factors.
Extract the common factor of 2: $- 2 \cdot \frac{1}{2} x^{3}$.
Cancel out the common factors.
Factor out 2 from the numerator: $- 2 \cdot \frac{1}{2} x^{3}$.
Eliminate the common factor: $- 2 x^{3}$.
Rewrite the result: $- 2 x^{3}$.
Divide by 1 to simplify: $- 2 x^{3}$.
Subtract the result from zero: $- 2 x^{3}$.
Express the integral in terms of $u$ and $du$: $\int \frac{1}{u} \cdot \frac{-1}{2} du$.
Simplify the integral.
Place the negative sign outside the integral: $- \int \frac{1}{u} \cdot \frac{1}{2} du$.
Combine the fraction: $- \int \frac{1}{2u} du$.
Rearrange the constant: $- \int \frac{1}{2u} du$.
Extract the constant $- \frac{1}{2}$ from the integral: $- \frac{1}{2} \int \frac{1}{u} du$.
Integrate $\frac{1}{u}$ with respect to $u$: $- \frac{1}{2} \ln |u| + C$.
Simplify the result: $- \frac{1}{2} \ln |u| + C$.
Substitute back the original expression for $u$: $- \frac{1}{2} \ln |5 - \frac{1}{2} x^{4}| + C$.
The process of solving the integral of a function using u-substitution involves several steps and the application of various calculus rules:
u-Substitution: This is a technique used to simplify integrals by substituting part of the integral with a new variable, typically denoted as $u$. The goal is to transform the integral into a simpler form that is easier to evaluate.
Differentiation Rules: The solution uses the Sum Rule, which states that the derivative of a sum is the sum of the derivatives, and the Power Rule, which states that the derivative of $x^n$ with respect to $x$ is $n x^{n-1}$.
Constant Multiple Rule: This rule is used when taking the derivative of a constant multiplied by a function. The derivative is the constant multiplied by the derivative of the function.
Integration: After simplifying the integral using u-substitution, the integral of $\frac{1}{u}$ with respect to $u$ is evaluated. The integral of $\frac{1}{u}$ is $\ln|u|$, where $\ln$ denotes the natural logarithm.
Back-Substitution: Once the integral is evaluated in terms of $u$, the original variable $x$ is substituted back in place of $u$ to express the result in terms of the original variable.
Constants of Integration: When performing indefinite integration, a constant of integration, typically denoted as $C$, is added to the result to account for the family of antiderivatives.
Throughout the process, algebraic manipulation, such as factoring and canceling common factors, is used to simplify expressions.