Integrate Using u-Substitution integral of x square root of 1+x with respect to x

Solution:

Step 1

Choose $u=1+x$ and calculate $du$.

Step 1.1

Set $u=1+x$ and determine $\frac{du}{dx}$.

Step 1.1.1

Differentiate $1+x$ to find $\frac{d}{dx}(1+x)$.

Step 1.1.2

Utilize the Sum Rule: the derivative of $1+x$ is the sum of the derivatives $\frac{d}{dx}(1)+\frac{d}{dx}(x)$.

Step 1.1.3

The derivative of a constant is zero, so $\frac{d}{dx}(1)=0$ and we have $0+\frac{d}{dx}(x)$.

Step 1.1.4

Apply the Power Rule: $\frac{d}{dx}(x^n)=n{x}^{n-1}$ for $n=1$, which gives us $0+1$.

Step 1.1.5

Combine the terms to get $du=dx$.

Step 1.2

Substitute $u$ and $du$ into the integral: $\int (u-1)\sqrt{u}du$.

Step 2

Express $\sqrt{u}$ as $u^{\frac{1}{2}}$: $\int (u-1)u^{\frac{1}{2}}du$.

Step 3

Expand the integrand $(u-1)u^{\frac{1}{2}}$.

Step 3.1

Distribute $u^{\frac{1}{2}}$ across $u-1$: $\int u{u}^{\frac{1}{2}}-1\cdot u^{\frac{1}{2}}du$.

Step 3.2

Raise $u$ to the first power: $\int u^1{u}^{\frac{1}{2}}-1\cdot u^{\frac{1}{2}}du$.

Step 3.3

Combine the exponents using $a^m{a}^n=a^{m+n}$: $\int u^{1+\frac{1}{2}}-1\cdot u^{\frac{1}{2}}du$.

Step 3.4

Express $1$ as a fraction: $\int u^{\frac{2}{2}+\frac{1}{2}}-1\cdot u^{\frac{1}{2}}du$.

Step 3.5

Add the exponents over a common denominator: $\int u^{\frac{3}{2}}-1\cdot u^{\frac{1}{2}}du$.

Step 3.6

Simplify the expression: $\int u^{\frac{3}{2}}-u^{\frac{1}{2}}du$.

Step 4

Separate the integral into two parts: $\int u^{\frac{3}{2}}du-\int u^{\frac{1}{2}}du$.

Step 5

Integrate $u^{\frac{3}{2}}$ using the Power Rule: $\frac{2}{5}{u}^{\frac{5}{2}}+C_1-\int u^{\frac{1}{2}}du$.

Step 6

Factor out the constant $-1$: $\frac{2}{5}{u}^{\frac{5}{2}}+C_1-\int u^{\frac{1}{2}}du$.

Step 7

Integrate $u^{\frac{1}{2}}$ using the Power Rule: $\frac{2}{5}{u}^{\frac{5}{2}}+C_1-(\frac{2}{3}{u}^{\frac{3}{2}}+C_2)$.

Step 8

Combine constants and simplify: $\frac{2}{5}{u}^{\frac{5}{2}}-\frac{2}{3}{u}^{\frac{3}{2}}+C$.

Step 9

Substitute back $1+x$ for $u$: $\frac{2}{5}(1+x{)}^{\frac{5}{2}}-\frac{2}{3}(1+x{)}^{\frac{3}{2}}+C$.

Knowledge Notes:

To solve the integral of $x\sqrt{1+x}$ using $u$-substitution, we follow these steps:

1. $u$-Substitution: This technique involves choosing a substitution $u=g(x)$ that simplifies the integral. The differential $du$ is then the derivative of $u$ with respect to $x$, multiplied by $dx$.

2. Sum Rule in Differentiation: The derivative of a sum of functions is the sum of the derivatives of those functions.

3. Constant Rule in Differentiation: The derivative of a constant is zero.

4. Power Rule in Differentiation: For any real number $n$, the derivative of $x^n$ with respect to $x$ is $n{x}^{n-1}$.

5. Distributive Property: This property allows us to multiply a sum by multiplying each addend separately and then sum the products.

6. Combining Exponents: When multiplying like bases, we add the exponents: $a^m\cdot a^n=a^{m+n}$.

7. Power Rule in Integration: The integral of $u^n$ with respect to $u$ is $\frac{u^{n+1}}{n+1}+C$, provided $n\ne -1$.

8. Simplifying Expressions: Combining like terms and simplifying expressions are important to reach the final form of the integral.

9. Back-Substitution: After integrating with respect to $u$, we substitute back the original variable to express the antiderivative in terms of the original variable.