Problem

Integrate Using u-Substitution integral of 1/(y square root of y) with respect to y

The problem is an integral calculus question where you are asked to evaluate the integral of a given function, 1/(y * √y), with respect to the variable y using the u-substitution method. U-substitution is a technique used to simplify integrals by substituting a part of the integrand with a new variable, u, which often converts the integral into a simpler form that is easier to evaluate. In this particular problem, you would typically look for a function within the integrand whose derivative is also present, or simplify the integrand to make the substitution apparent, and then proceed with the integration after substituting the identified part with u.

1yydy

Answer

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Solution:

Step 1:

We cannot use u-substitution to solve this integral. An alternative approach will be used.

Step 2:

Begin by simplifying the integrand.

Step 2.1:

Start simplification.

Step 2.1.1:

Convert the square root to an exponent using the rule axn=axn. Thus, y becomes y12. The integral now is 1yy12dy.

Step 2.1.2:

Combine the terms y and y12 by summing their exponents.

Step 2.1.2.1:

Combine y and y12.

Step 2.1.2.1.1:

Express y as y1. The integral becomes 1y1y12dy.

Step 2.1.2.1.2:

Apply the exponent rule aman=am+n to combine the exponents. The integral simplifies to 1y1+12dy.

Step 2.1.2.2:

Express the number 1 as a fraction with a common denominator. The integral is now 1y22+12dy.

Step 2.1.2.3:

Combine the numerators over the common denominator. The integral is 1y2+12dy.

Step 2.1.2.4:

Add the numbers 2 and 1. The integral becomes 1y32dy.

Step 2.2:

Now apply the basic rules of exponents.

Step 2.2.1:

Rewrite y32 as a negative exponent by raising it to the power of 1. The integral is (y32)1dy.

Step 2.2.2:

Multiply the exponents in (y32)1.

Step 2.2.2.1:

Use the power rule for exponents, (am)n=amn. The integral becomes y321dy.

Step 2.2.2.2:

Perform the multiplication of 321.

Step 2.2.2.2.1:

Combine 32 and 1. The integral is now y312dy.

Step 2.2.2.2.2:

Multiply 3 by 1. The integral simplifies to y32dy.

Step 2.2.2.3:

Bring the negative sign in front of the fraction. The integral is y32dy.

Step 3:

According to the Power Rule for integration, the integral of y32 with respect to y is 2y12+C.

Step 4:

Finally, simplify the result.

Step 4.1:

Rewrite 2y12+C as 21y12+C.

Step 4.2:

Proceed with simplification.

Step 4.2.1:

Combine 2 and 1y12. The result is 2y12+C.

Step 4.2.2:

Place the negative sign in front of the fraction to get the final answer: 2y12+C.

Knowledge Notes:

  1. u-Substitution: A technique used in integration, which involves substituting a part of the integrand with a new variable 'u' to simplify the integral. It's not applicable in this case.

  2. Simplifying the Integrand: Before integrating, it can be helpful to simplify the expression by rewriting square roots as exponents and combining like terms.

  3. Exponent Rules: Important rules include axn=axn, aman=am+n, and (am)n=amn. These rules are used to simplify the integrand before integrating.

  4. Power Rule for Integration: For any real number n1, the integral of xn with respect to x is xn+1n+1+C, where C is the constant of integration. This rule is used to find the antiderivative of the given function.

  5. Negative Exponents: A term with a negative exponent, such as xn, can be rewritten as 1xn. This is used to move terms from the denominator to the numerator or vice versa when simplifying expressions.

  6. Constants of Integration: When performing indefinite integration, a constant of integration (denoted as 'C') is added to the result to account for all possible antiderivatives.

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