Integrate Using u-Substitution integral of x^2 square root of x^3+33 with respect to x , u=x^3+33
The given problem is asking for the evaluation of an indefinite integral of a function involving a power of x and a square root of a polynomial expression in x. Specifically, the task is to find the antiderivative of x^2 times the square root of (x^3 + 33). The question hints at using the method of u-substitution, a common technique in calculus for simplifying integrals. U-substitution involves choosing a part of the integrand to substitute with a new variable u, such that the integral becomes easier to evaluate when expressed in terms of u. The chosen u in this case is suggested as u = x^3 + 33. This substitution is likely to simplify the integrand, as taking the derivative of u with respect to x will introduce a factor related to x^2, which is present in the original integrand. This could potentially transform the integral into a form involving u that is more straightforward to integrate.
Choose
Set
Take the derivative of
Apply the Sum Rule to find the derivative of
Use the Power Rule, which states that the derivative of
Since the derivative of a constant is zero, the derivative of 33 with respect to
Combine
Substitute
Extract the constant
Express
Integrate
Simplify the expression.
Rewrite the expression as a product:
Multiply the constants:
Substitute back the original variable:
The problem involves integration using u-substitution, a technique often used to simplify integrals by changing the variable of integration. Here are the relevant knowledge points:
u-Substitution: This is a method for evaluating integrals. By choosing
Derivative Rules: The Sum Rule states that the derivative of a sum is the sum of the derivatives. The Power Rule states that the derivative of
Constant Multiple Rule: A constant can be factored out of the integral, which simplifies the integration process.
Integration of Power Functions: When integrating power functions of the form
Simplifying Expressions: After integration, it's common to simplify the expression by multiplying out constants and combining like terms.
Back Substitution: After integrating with respect to