Problem

Integrate Using u-Substitution integral of x^2 square root of x^3+33 with respect to x , u=x^3+33

The given problem is asking for the evaluation of an indefinite integral of a function involving a power of x and a square root of a polynomial expression in x. Specifically, the task is to find the antiderivative of x^2 times the square root of (x^3 + 33). The question hints at using the method of u-substitution, a common technique in calculus for simplifying integrals. U-substitution involves choosing a part of the integrand to substitute with a new variable u, such that the integral becomes easier to evaluate when expressed in terms of u. The chosen u in this case is suggested as u = x^3 + 33. This substitution is likely to simplify the integrand, as taking the derivative of u with respect to x will introduce a factor related to x^2, which is present in the original integrand. This could potentially transform the integral into a form involving u that is more straightforward to integrate.

x2x3+33dx,u=x3+33

Answer

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Solution:

Step:1

Choose u=x3+33. Consequently, du=3x2dx. Express the integral in terms of u and du.

Step:1.1

Set u=x3+33 and compute dudx.

Step:1.1.1

Take the derivative of x3+33. ddx(x3+33)

Step:1.1.2

Apply the Sum Rule to find the derivative of x3+33 with respect to x: ddx(x3)+ddx(33).

Step:1.1.3

Use the Power Rule, which states that the derivative of xn is nxn1 for n=3: 3x2+ddx(33).

Step:1.1.4

Since the derivative of a constant is zero, the derivative of 33 with respect to x is 0: 3x2+0.

Step:1.1.5

Combine 3x2 and 0: 3x2.

Step:1.2

Substitute u and du into the integral: u3du.

Step:2

Extract the constant 13 from the integral: 13udu.

Step:3

Express u as a power of u: 13u12du.

Step:4

Integrate u12 with respect to u using the Power Rule: 13(23u32+C).

Step:5

Simplify the expression.

Step:5.1

Rewrite the expression as a product: 1323u32+C.

Step:5.2

Multiply the constants: 29u32+C.

Step:6

Substitute back the original variable: 29(x3+33)32+C.

Knowledge Notes:

The problem involves integration using u-substitution, a technique often used to simplify integrals by changing the variable of integration. Here are the relevant knowledge points:

  1. u-Substitution: This is a method for evaluating integrals. By choosing u as a function of x, we can transform the integral into a simpler form. The differential du is then the derivative of u with respect to x multiplied by dx.

  2. Derivative Rules: The Sum Rule states that the derivative of a sum is the sum of the derivatives. The Power Rule states that the derivative of xn is nxn1.

  3. Constant Multiple Rule: A constant can be factored out of the integral, which simplifies the integration process.

  4. Integration of Power Functions: When integrating power functions of the form un, the Power Rule for integration states that undu=1n+1un+1+C, where C is the constant of integration.

  5. Simplifying Expressions: After integration, it's common to simplify the expression by multiplying out constants and combining like terms.

  6. Back Substitution: After integrating with respect to u, we substitute back in terms of the original variable x to complete the problem.

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