Find the Antiderivative f(t)=0.8t-15.9
The problem asks to determine the antiderivative (also known as the indefinite integral) of the given function f(t), which is a linear function in terms of t. Specifically, the problem provides the function f(t) = 0.8t - 15.9 and requires the calculation of the function F(t) such that the derivative of F(t) with respect to t is equal to 0.8t - 15.9. The antiderivative is a general expression involving a constant of integration, since the derivative of a constant is zero.
$f \left(\right. t \left.\right) = 0.8 t - 15.9$
Identify the antiderivative $F(t)$ by integrating the given function $f(t)$.
$F(t) = \int f(t) \, dt$
Write down the integral that needs to be solved.
$F(t) = \int (0.8t - 15.9) \, dt$
Decompose the integral into separate terms.
$\int 0.8t \, dt + \int (-15.9) \, dt$
Extract the constant coefficient $0.8$ from the first integral.
$0.8 \int t \, dt - \int 15.9 \, dt$
Utilize the Power Rule for integration on the variable $t$.
$0.8 \left( \frac{t^2}{2} + C \right) - \int 15.9 \, dt$
Apply the rule for integrating constants.
$0.8 \left( \frac{t^2}{2} + C \right) - 15.9t + C$
Simplify the expression.
Combine the constants with the variable term.
$0.8 \left( \frac{t^2}{2} + C \right) - 15.9t + C$
Perform the simplification.
$\frac{4}{5} \cdot \frac{t^2}{2} - 15.9t + C$
Reorder the terms for the final antiderivative.
$\frac{4t^2}{10} - 15.9t + C$
Present the antiderivative of the function $f(t) = 0.8t - 15.9$.
$F(t) = \frac{4t^2}{10} - 15.9t + C$
The process of finding an antiderivative, also known as the indefinite integral, involves reversing the process of differentiation. Here are the relevant knowledge points used in solving the problem:
Indefinite Integral: The antiderivative of a function $f(t)$ is represented by the integral sign without bounds, $\int f(t) \, dt$, and includes an arbitrary constant $C$ since the derivative of a constant is zero.
Linearity of Integration: The integral of a sum of functions is equal to the sum of their integrals. This property allows us to split the integral of $0.8t - 15.9$ into two separate integrals.
Constant Multiple Rule: If a constant is multiplied by a function, it can be factored out of the integral. This is why we can move $0.8$ outside of the integral in Step 4.
Power Rule for Integration: For any real number $n \neq -1$, the integral of $t^n$ with respect to $t$ is $\frac{t^{n+1}}{n+1} + C$. This is applied in Step 5 where $n=1$.
Constant Rule: The integral of a constant is equal to the constant multiplied by the variable of integration. This is applied in Step 6 for the term $-15.9$.
Simplification: Combining like terms and simplifying coefficients is a standard algebraic process applied in Step 7 to obtain the final antiderivative expression.
In summary, the problem-solving process involves recognizing the structure of the function to be integrated, applying the rules of integration, and simplifying the result to find the antiderivative.