Problem

Find the Difference Quotient f(x)=-2x^2-x

The problem asks you to calculate the difference quotient for the quadratic function f(x) = -2x^2 - x. The difference quotient is a way to express the slope of the secant line between two points on a graph of the function, which is a method used in calculus to approach the concept of derivatives. The difference quotient is typically represented by the formula:

(f(x + h) - f(x)) / h

where h is a small increment in x. For this specific problem, you are expected to substitute the given function into the difference quotient formula and simplify as much as possible.

f(x)=2x2x

Answer

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Solution:

Step 1:

Utilize the formula for the difference quotient: f(x+h)f(x)h.

Step 2:

Determine the function values required by the formula.

Step 2.1:

Calculate f(x+h).

Step 2.1.1:

Substitute x with (x+h) in the function: f(x+h)=2(x+h)2(x+h).

Step 2.1.2:

Expand and simplify the expression.

Step 2.1.2.1:

Expand each term individually.

Step 2.1.2.1.1:

Express (x+h)2 as (x+h)(x+h): f(x+h)=2((x+h)(x+h))(x+h).

Step 2.1.2.1.2:

Use the FOIL method to expand (x+h)(x+h).

Step 2.1.2.1.2.1:

Distribute the terms: f(x+h)=2(x(x+h)+h(x+h))(x+h).

Step 2.1.2.1.2.2:

Continue distribution: f(x+h)=2(xx+xh+hx+hh)(x+h).

Step 2.1.2.1.2.3:

Complete distribution: f(x+h)=2(xx+xh+hx+hh)(x+h).

Step 2.1.2.1.3:

Combine like terms and simplify.

Step 2.1.2.1.3.1:

Simplify each term.

Step 2.1.2.1.3.1.1:

Multiply x by itself: f(x+h)=2(x2+xh+hx+hh)(x+h).

Step 2.1.2.1.3.1.2:

Multiply h by itself: f(x+h)=2(x2+xh+hx+h2)(x+h).

Step 2.1.2.1.3.2:

Combine xh and hx.

Step 2.1.2.1.3.2.1:

Rearrange terms: f(x+h)=2(x2+hx+hx+h2)(x+h).

Step 2.1.2.1.3.2.2:

Combine hx and hx: f(x+h)=2(x2+2hx+h2)(x+h).

Step 2.1.2.1.4:

Distribute the negative sign: f(x+h)=2x22(2hx)2h2(x+h).

Step 2.1.2.1.5:

Multiply 2 by 2: f(x+h)=2x24(hx)2h2(x+h).

Step 2.1.2.1.6:

Finish distribution: f(x+h)=2x24hx2h2xh.

Step 2.1.2.2:

The simplified result is 2x24hx2h2xh.

Step 2.2:

Rearrange the terms.

Step 2.2.1:

Move x: 2x24hx2h2hx.

Step 2.2.2:

Move 2x2: 4hx2h22x2hx.

Step 2.2.3:

Rearrange 4hx and 2h2: 2h24hx2x2hx.

Step 2.3:

Calculate f(x) and combine with f(x+h).

Step 3:

Insert the function values into the difference quotient: f(x+h)f(x)h=2h24hx2x2hx(2x2x)h.

Step 4:

Simplify the expression.

Step 4.1:

Simplify the numerator.

Step 4.1.1:

Apply the distributive property: 2h24hx2x2hx+2x2(x)h.

Step 4.1.2:

Multiply 2 by 1: 2h24hx2x2hx+2x2+xh.

Step 4.1.3:

Multiply (x).

Step 4.1.3.1:

Multiply 1 by 1: 2h24hx2x2hx+2x2+xh.

Step 4.1.3.2:

Multiply x by 1: 2h24hx2x2hx+2x2+xh.

Step 4.1.4:

Add 2x2 and 2x2: 2h24hxhx+0+xh.

Step 4.1.5:

Combine 2h2 and 0: 2h24hxhx+xh.

Step 4.1.6:

Combine x and x: 2h24hxh+0h.

Step 4.1.7:

Combine 2h24hxh and 0: 2h24hxhh.

Step 4.1.8:

Factor out h from 2h24hxh.

Step 4.1.8.1:

Factor h from 2h2: h(2h)4hxhh.

Step 4.1.8.2:

Factor h from 4hx: h(2h)+h(4x)hh.

Step 4.1.8.3:

Factor h from h: h(2h)+h(4x)+h(1)h.

Step 4.1.8.4:

Factor h from h(2h)+h(4x): h(2h4x)+h(1)h.

Step 4.1.8.5:

Factor h from h(2h4x)+h(1): h(2h4x1)h.

Step 4.2:

Cancel out the common h factors.

Step 4.2.1:

Eliminate the common h factor.

Step 4.2.1.1:

Cancel h: h(2h4x1)h.

Step 4.2.1.2:

Divide 2h4x1 by 1: 2h4x1.

Step 4.2.2:

Rearrange 2h and 4x: 4x2h1.

Step 5:

The difference quotient is 4x2h1.

Knowledge Notes:

The problem involves finding the difference quotient for the function f(x)=2x2x. The difference quotient is a way to measure the average rate of change of a function over an interval and is defined as f(x+h)f(x)h, where h is the difference between two inputs of the function.

To solve this problem, one must understand several concepts:

  1. Function evaluation: Substituting a specific value into a function.

  2. Algebraic simplification: Combining like terms and simplifying expressions.

  3. The FOIL method: A technique for multiplying two binomials, which stands for First, Outer, Inner, Last.

  4. The distributive property: A property that allows one to distribute a multiplication over addition or subtraction within parentheses.

  5. Factoring: The process of breaking down an expression into its component factors.

  6. Cancelling common factors: Reducing fractions by eliminating common factors in the numerator and denominator.

The solution involves applying these concepts to evaluate f(x+h), simplify the resulting expression, and then calculate the difference quotient by subtracting f(x) and dividing by h. The final step is to simplify the expression by factoring and cancelling common factors, yielding the simplified difference quotient.

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