Problem

Find the x and y Intercepts y=-6x^2-5x-1

This problem is asking for the points where the graph of the given quadratic equation intersects the x-axis and y-axis. The x-intercepts (also called 'roots') are the values of x where the equation y = -6x^2 - 5x - 1 equals zero, while the y-intercept is the value of y when x is zero. Because the equation is quadratic, you may expect two x-intercepts (unless the discriminant is zero, in which case there would be a single x-intercept, or it is negative, in which case there would be no real x-intercepts). The y-intercept is straightforward to find, as it requires substituting x with zero and solving for y.

y=6x25x1

Answer

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Solution:

Step:1

Determine the x-intercepts.

Step:1.1

Set y to 0 and solve for x: 0=6x25x1.

Step:1.2

Proceed to solve the quadratic equation.

Step:1.2.1

Rewrite the equation as 6x25x1=0.

Step:1.2.2

Begin factoring the quadratic expression.

Step:1.2.2.1

Extract 1 from each term: (6x2+5x+1)=0.

Step:1.2.2.2

Attempt to factor by grouping.

Step:1.2.2.2.1

Split the middle term to factor by grouping, ensuring the two terms multiply to 61=6 and add up to 5.

Step:1.2.2.2.2

Factor out the common factor from each binomial: (2x(3x+1)+1(3x+1))=0.

Step:1.2.2.2.3

Factor out the common binomial factor: (3x+1)(2x+1)=0.

Step:1.2.3

Set each factor equal to 0: 3x+1=0 and 2x+1=0.

Step:1.2.4

Solve 3x+1=0 for x: x=13.

Step:1.2.5

Solve 2x+1=0 for x: x=12.

Step:1.2.6

The solutions are x=13 and x=12.

Step:1.3

Express the x-intercepts as ordered pairs: (13,0) and (12,0).

Step:2

Identify the y-intercepts.

Step:2.1

Set x to 0 and solve for y: y=6(0)2501.

Step:2.2

Simplify the equation to find y: y=1.

Step:2.3

Express the y-intercept as an ordered pair: (0,1).

Step:3

Combine the intercepts.

List the x-intercepts and y-intercept: (13,0), (12,0), and (0,1).

Knowledge Notes:

To find the x-intercepts of a function, we set y to 0 and solve the resulting equation for x. The x-intercepts are the points where the graph of the function crosses the x-axis.

To find the y-intercepts, we set x to 0 and solve for y. The y-intercepts are the points where the graph of the function crosses the y-axis.

The quadratic equation ax2+bx+c=0 can be solved by factoring, completing the square, or using the quadratic formula. In this case, we attempted to factor the equation.

Factoring by grouping is a method used when a polynomial does not factor easily. It involves rearranging and grouping terms to find common factors.

The distributive property, a(b+c)=ab+ac, is used in the factoring process.

The solutions to the quadratic equation are the values of x that make the equation true, and these correspond to the x-intercepts of the graph.

Ordered pairs are used to represent points on a coordinate plane, with the x-coordinate first and the y-coordinate second, in the form (x,y).

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