Find the Antiderivative f(x)=x^2-3x+2
The problem asks you to determine the antiderivative, also known as the indefinite integral, of the given function f(x) = x^2 - 3x + 2. This entails finding a function F(x) such that the derivative of F(x) with respect to x is f(x). Essentially, it is the reverse process of differentiation.
$f \left(\right. x \left.\right) = x^{2} - 3 x + 2$
Identify the antiderivative $F(x)$ by integrating the given function $f(x)$.
$F(x) = \int f(x) \, dx$
Write out the integral that needs to be solved.
$F(x) = \int (x^2 - 3x + 2) \, dx$
Decompose the integral into separate integrals for each term.
$\int x^2 \, dx - \int 3x \, dx + \int 2 \, dx$
Use the Power Rule to integrate $x^2$.
$\frac{x^3}{3} + C_1 - \int 3x \, dx + \int 2 \, dx$
Factor out the constant $-3$ from the integral.
$\frac{x^3}{3} + C_1 - 3\int x \, dx + \int 2 \, dx$
Integrate $x$ using the Power Rule.
$\frac{x^3}{3} + C_1 - 3\left(\frac{x^2}{2} + C_2\right) + \int 2 \, dx$
Apply the constant rule to integrate 2.
$\frac{x^3}{3} + C_1 - 3\left(\frac{x^2}{2} + C_2\right) + 2x + C_3$
Simplify the expression.
Combine like terms.
$\frac{x^3}{3} + C_1 - \frac{3x^2}{2} - 3C_2 + 2x + C_3$
Simplify further.
$\frac{x^3}{3} - \frac{3x^2}{2} + 2x + C$ (where $C = C_1 - 3C_2 + C_3$)
Reorder the terms for the final antiderivative.
$\frac{1}{3}x^3 - \frac{3}{2}x^2 + 2x + C$
Conclude with the antiderivative of $f(x) = x^2 - 3x + 2$.
$F(x) = \frac{1}{3}x^3 - \frac{3}{2}x^2 + 2x + C$
The process of finding the antiderivative involves several key concepts in calculus:
Indefinite Integral: The antiderivative of a function $f(x)$ is found by calculating the indefinite integral, denoted as $\int f(x) \, dx$. This represents the family of all functions whose derivative is $f(x)$.
Power Rule for Integration: To integrate a power of $x$, use the formula $\int x^n \, dx = \frac{x^{n+1}}{n+1} + C$ for any real number $n \neq -1$, where $C$ is the constant of integration.
Linearity of Integration: The integral of a sum or difference of functions is the sum or difference of their integrals, i.e., $\int (f(x) \pm g(x)) \, dx = \int f(x) \, dx \pm \int g(x) \, dx$.
Constant Multiple Rule: A constant factor can be pulled out of the integral, $\int k \cdot f(x) \, dx = k \cdot \int f(x) \, dx$, where $k$ is a constant.
Constant Rule: The integral of a constant $k$ is $kx + C$, where $C$ is the constant of integration.
Combining Constants: When multiple constants of integration appear in a calculation, they can be combined into a single constant because the antiderivative is defined up to an arbitrary constant.
By applying these principles, one can systematically find the antiderivative of a polynomial function like $f(x) = x^2 - 3x + 2$.