Problem

Find the Axis of Symmetry f(x)=(x-5)^2-9

The given problem is asking for the determination of the axis of symmetry of the quadratic function f(x) = (x-5)^2 - 9. The axis of symmetry is a vertical line that divides the graph of the quadratic function into two mirror images. For a quadratic function in the form f(x) = (x-h)^2 + k, the axis of symmetry can be found by identifying the value of h, which corresponds to the x-coordinate of the vertex of the parabola described by the quadratic function.

$f \left(\right. x \left.\right) = \left(\left(\right. x - 5 \left.\right)\right)^{2} - 9$

Answer

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Solution:

Step:1

Represent the function $f(x) = (x-5)^2-9$ in standard equation form as $y = (x-5)^2-9$.

Step:2

Identify the coefficients $a$, $h$, and $k$ by comparing with the vertex form $y = a(x - h)^2 + k$.

  • $a = 1$
  • $h = 5$
  • $k = -9$

Step:3

Determine the direction in which the parabola opens based on the sign of $a$.

  • Since $a$ is positive, the parabola opens upwards.

Step:4

Locate the vertex of the parabola using the coordinates $(h, k)$.

  • Vertex: $(5, -9)$

Step:5

Calculate the distance $p$ from the vertex to the focus of the parabola.

Step:5.1

Use the formula for $p$ which is $\frac{1}{4a}$.

Step:5.2

Insert the value of $a$ into the formula to get $p$.

  • $p = \frac{1}{4 \cdot 1}$
Step:5.3

Simplify the expression by removing common factors.

Step:5.3.1

Eliminate the common factor of $1$.

  • $p = \frac{\cancel{1}}{4 \cdot \cancel{1}}$
Step:5.3.2

Express the simplified form of $p$.

  • $p = \frac{1}{4}$

Step:6

Determine the focus of the parabola.

Step:6.1

For a parabola that opens up or down, the focus is found by adding $p$ to the y-coordinate $k$ of the vertex.

  • Focus: $(h, k + p)$
Step:6.2

Substitute the known values for $h$, $k$, and $p$ to find the focus.

  • Focus: $(5, -9 + \frac{1}{4})$
  • Focus: $(5, -\frac{35}{4})$

Step:7

Identify the axis of symmetry, which is the vertical line passing through both the vertex and the focus.

  • Axis of Symmetry: $x = 5$

Knowledge Notes:

The problem involves finding the axis of symmetry for a given quadratic function. The quadratic function is presented in the form $f(x) = (x-5)^2-9$, which is a transformation of the standard form $y = ax^2 + bx + c$. The steps taken to solve the problem are based on the properties of parabolas and their symmetrical nature.

  1. Vertex Form of a Parabola: The vertex form is $y = a(x - h)^2 + k$, where $(h, k)$ is the vertex of the parabola, and $a$ determines the direction and width of the parabola. If $a > 0$, the parabola opens upwards, and if $a < 0$, it opens downwards.

  2. Axis of Symmetry: For a parabola, the axis of symmetry is a vertical line that passes through the vertex. The equation of the axis of symmetry is always $x = h$, where $h$ is the x-coordinate of the vertex.

  3. Focus of a Parabola: The focus is a point inside the parabola where all the reflected rays (assuming the parabola is a mirror) meet. The distance $p$ from the vertex to the focus can be calculated using the formula $p = \frac{1}{4a}$.

  4. Simplifying Expressions: In the process of solving, simplification of fractions and expressions is often required to get to the final answer.

  5. Parabola Opening Direction: The sign of the coefficient $a$ in the vertex form of a parabola determines whether the parabola opens upwards ($a > 0$) or downwards ($a < 0$).

By following the steps outlined in the solution, one can find the axis of symmetry for any quadratic function presented in vertex form.

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