Find the Antiderivative f(x)=x(9-x)^2
This problem is asking you to compute the antiderivative, also known as the indefinite integral, of the given function f(x) = x(9-x)^2. The antiderivative is the function F(x) such that its derivative F'(x) equals the given function f(x). The process involves reversing the differentiation operation to find a function whose derivative returns the original function. In this specific problem, you need to find a function F(x) that, when differentiated, will give you x times the square of (9-x).
$f \left(\right. x \left.\right) = x \left(\left(\right. 9 - x \left.\right)\right)^{2}$
Identify the antiderivative $F(x)$ by integrating the function $f(x)$.
$F(x) = \int f(x) \, dx$
Write down the integral that needs to be solved.
$F(x) = \int x(9 - x)^2 \, dx$
Perform a substitution to simplify the integral. Let $u = 9 - x$, then $du = -dx$ which implies $-du = dx$.
Define the substitution $u = 9 - x$ and calculate $\frac{du}{dx}$.
Take the derivative of $9 - x$.
$\frac{d}{dx}(9 - x)$
Differentiate the expression.
Apply the Sum Rule to find the derivative of $9 - x$ with respect to $x$.
$\frac{d}{dx}(9) + \frac{d}{dx}(-x)$
The derivative of a constant is zero, so the derivative of $9$ with respect to $x$ is $0$.
$0 + \frac{d}{dx}(-x)$
Compute $\frac{d}{dx}(-x)$.
The derivative of $-x$ with respect to $x$ is $-1$ times the derivative of $x$ with respect to $x$.
$0 - \frac{d}{dx}(x)$
Apply the Power Rule which states that the derivative of $x^n$ is $nx^{n-1}$ where $n = 1$.
$0 - 1 \cdot 1$
Multiply $-1$ by $1$.
$0 - 1$
Combine the terms to get $-1$.
$-1$
Express the integral in terms of $u$ and $du$.
$\int -(-u + 9)u^2 \, du$
Expand the expression $-(-u + 9)u^2$.
Apply the distributive property to the expression.
$\int (u - 9)u^2 \, du$
Distribute the negative sign.
$\int u^3 - 9u^2 \, du$
Decompose the integral into simpler integrals.
$\int u^3 \, du - 9\int u^2 \, du$
Integrate $u^3$ with respect to $u$ using the Power Rule.
$\frac{1}{4}u^4 + C - 9\int u^2 \, du$
Take the constant $-9$ outside the integral.
$\frac{1}{4}u^4 + C - 9\int u^2 \, du$
Integrate $u^2$ with respect to $u$ using the Power Rule.
$\frac{1}{4}u^4 + C - 9\left(\frac{1}{3}u^3 + C\right)$
Simplify the expression.
Combine like terms.
$\frac{1}{4}u^4 - 3u^3 + C$
Substitute back $u = 9 - x$ into the antiderivative.
$\frac{1}{4}(9 - x)^4 - 3(9 - x)^3 + C$
Conclude with the antiderivative $F(x)$ of the function $f(x) = x(9 - x)^2$.
$F(x) = \frac{1}{4}(9 - x)^4 - 3(9 - x)^3 + C$
The problem involves finding the antiderivative of a given function, which is the reverse process of differentiation. The antiderivative is also known as the indefinite integral. The process of integration is used to find the antiderivative.
Integration: The process of finding the function $F(x)$ whose derivative is the given function $f(x)$.
Substitution Method: A technique used to simplify integrals by substituting a part of the integral with a new variable.
Sum Rule for Derivatives: The derivative of a sum of functions is the sum of the derivatives of those functions.
Power Rule for Derivatives: The derivative of $x^n$ with respect to $x$ is $nx^{n-1}$.
Power Rule for Integration: The integral of $x^n$ with respect to $x$ is $\frac{1}{n+1}x^{n+1}$ plus a constant of integration, provided $n \neq -1$.
Constant Multiple Rule: A constant can be moved in and out of the integral.
Simplifying Expressions: Combining like terms and simplifying expressions are algebraic techniques used to make expressions more manageable.
The solution provided follows the same step-by-step format as the original problem-solving process, including the use of substitution, differentiation, and integration rules. Each step is clearly marked and explained, and the mathematical expressions are rendered in LaTeX format for clarity.