Problem

Find dy/dx e^x-y=xy^3+e^2-18

The given problem is asking for the derivative of y with respect to x, denoted as dy/dx, of the implicit function e^x - y = xy^3 + e^2 - 18. An implicit function is one where y is not isolated on one side of the equation but is mixed with x. To find dy/dx, you will need to differentiate both sides of the equation with respect to x, applying the chain rule, product rule, and implicit differentiation methods. The goal is to solve for dy/dx in terms of x, y, or both.

$e^{x} - y = x y^{3} + e^{2} - 18$

Answer

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Solution:

Step 1

Take the derivative of both sides with respect to $x$: $\frac{d}{dx}(e^x - y) = \frac{d}{dx}(xy^3 + e^2 - 18)$.

Step 2

Differentiate the left-hand side:

Step 2.1

Apply the Sum Rule: $\frac{d}{dx}(e^x) + \frac{d}{dx}(-y)$.

Step 2.2

Use the Exponential Rule: $e^x \ln(e) + \frac{d}{dx}(-y)$, noting that $\ln(e) = 1$.

Step 2.3

Find the derivative of $-y$:

Step 2.3.1

Since $-1$ is a constant, $\frac{d}{dx}(-y) = -\frac{d}{dx}(y)$.

Step 2.3.2

Represent $\frac{d}{dx}(y)$ as $y'$: $e^x - y'$.

Step 3

Differentiate the right-hand side:

Step 3.1

Use the Sum Rule: $\frac{d}{dx}(xy^3) + \frac{d}{dx}(e^2) + \frac{d}{dx}(-18)$.

Step 3.2

Find the derivative of $xy^3$:

Step 3.2.1

Apply the Product Rule: $y^3 \frac{d}{dx}(x) + x \frac{d}{dx}(y^3)$.

Step 3.2.2

Use the Chain Rule for $y^3$:

Step 3.2.2.1

Let $u = y$: $x(3u^2 \frac{d}{dx}(y)) + y^3$.

Step 3.2.2.2

Apply the Power Rule: $x(3y^2 y') + y^3$.

Step 3.2.2.3

Substitute $u$ back with $y$: $x(3y^2 y') + y^3$.

Step 3.3

Differentiate the constants:

Step 3.3.1

Since $e^2$ is constant, its derivative is $0$.

Step 3.3.2

The derivative of $-18$ is also $0$.

Step 3.4

Simplify the expression: $y^3 + 3xy^2 y'$.

Step 4

Combine the differentiated left and right sides: $e^x - y' = y^3 + 3xy^2 y'$.

Step 5

Solve for $y'$:

Step 5.1

Isolate terms involving $y'$: $e^x - y^3 = y' + 3xy^2 y'$.

Step 5.2

Factor out $y'$: $y'(1 + 3xy^2) = e^x - y^3$.

Step 5.3

Divide both sides by $(1 + 3xy^2)$ to solve for $y'$.

Step 5.4

Simplify the expression for $y'$: $y' = \frac{e^x - y^3}{1 + 3xy^2}$.

Step 6

Replace $y'$ with $\frac{dy}{dx}$: $\frac{dy}{dx} = \frac{e^x - y^3}{1 + 3xy^2}$.

Knowledge Notes:

  1. Sum Rule: The derivative of a sum of functions is the sum of the derivatives of those functions.

  2. Exponential Rule: The derivative of $e^x$ is $e^x$. More generally, the derivative of $a^x$ is $a^x \ln(a)$.

  3. Product Rule: The derivative of a product of two functions $f(x)g(x)$ is given by $f'(x)g(x) + f(x)g'(x)$.

  4. Chain Rule: The derivative of a composite function $f(g(x))$ is $f'(g(x))g'(x)$.

  5. Power Rule: The derivative of $x^n$ with respect to $x$ is $nx^{n-1}$.

  6. Constant Rule: The derivative of a constant is zero.

  7. Implicit Differentiation: When a function is not given in the form $y=f(x)$, we differentiate both sides of the equation with respect to $x$ and solve for $\frac{dy}{dx}$.

  8. Notation: The notation $y'$ and $\frac{dy}{dx}$ both represent the derivative of $y$ with respect to $x$.

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