Evaluate the Summation sum from k=5 to 13 of (5-2k)/8
The question asks for an evaluation of a finite sum. Specifically, it is asking to sum up a series of terms that are described by the formula (5-2k)/8, where k takes on integer values starting from 5 and ending at 13. Each term of the series should be computed with a different k value and then all these terms should be added together to find the total sum. This problem involves basic arithmetic and understanding of summation notation used in mathematics.
$\sum_{k = 5}^{13} \frac{5 - 2 k}{8}$
Adjust the summation's starting index to 1 by separating the original summation into two parts.
$$\sum_{k = 5}^{13} \frac{5 - 2k}{8} = \sum_{k = 1}^{13} \frac{5 - 2k}{8} - \sum_{k = 1}^{4} \frac{5 - 2k}{8}$$
Calculate the first summation $\sum_{k = 1}^{13} \frac{5 - 2k}{8}$.
Break down the summation into two simpler summations.
$$\sum_{k = 1}^{13} \frac{5}{8} - \sum_{k = 1}^{13} \frac{2k}{8}$$
Compute the summation of the constant term $\sum_{k = 1}^{13} \frac{5}{8}$.
Apply the constant summation formula.
$$\sum_{k = 1}^{n} c = cn$$
Insert the given values into the formula.
$$\frac{5}{8} \cdot 13$$
Perform the multiplication.
$$\frac{5 \cdot 13}{8}$$ $$\frac{65}{8}$$
Compute the summation involving $k$, $\sum_{k = 1}^{13} \frac{2k}{8}$.
Extract the constant factor from the summation.
$$-\frac{1}{4} \sum_{k = 1}^{13} k$$
Utilize the arithmetic series formula.
$$\sum_{k = 1}^{n} k = \frac{n(n + 1)}{2}$$
Substitute the values into the formula and include the constant factor.
$$-\frac{1}{4} \cdot \frac{13(13 + 1)}{2}$$
Simplify the expression.
$$-\frac{1}{4} \cdot \frac{13 \cdot 14}{2}$$ $$-\frac{1}{4} \cdot \frac{182}{2}$$ $$-\frac{91}{4}$$
Combine the results of the two summations.
$$\frac{65}{8} - \frac{91}{4}$$
Simplify the expression to a common denominator.
Convert $-\frac{91}{4}$ to have a denominator of 8.
$$\frac{65}{8} - \frac{91 \cdot 2}{8}$$
Combine the numerators over the common denominator.
$$\frac{65 - 182}{8}$$
Simplify the numerator.
$$\frac{-117}{8}$$
Calculate the second summation $\sum_{k = 1}^{4} \frac{5 - 2k}{8}$.
Write out the terms for each value of $k$.
$$\frac{5}{8} - \frac{1}{4} + \frac{5}{8} - \frac{1}{2} + \frac{5}{8} - \frac{3}{4} + \frac{5}{8} - 1$$
Simplify the series.
Combine like terms.
$$\frac{20}{8} - \frac{10}{4}$$
Reduce the fractions to simplest form.
$$\frac{5}{2} - \frac{5}{2}$$
Subtract the fractions.
$$0$$
Substitute the summation results with their evaluated values.
$$- \frac{117}{8} - 0$$
Combine the final terms.
$$- \frac{117}{8}$$
Present the result in various formats.
Exact Form:
$$- \frac{117}{8}$$
Decimal Form:
$$- 14.625$$
Mixed Number Form:
$$- 14 \frac{5}{8}$$
The problem involves evaluating a finite summation, which is a common task in algebra and calculus. The relevant knowledge points include:
Summation Notation: The sigma notation $\sum$ is used to represent the sum of a sequence of terms. The index of summation and the upper and lower bounds indicate the range of values to be summed.
Arithmetic Series: The sum of the first $n$ natural numbers is given by the formula $\sum_{k=1}^{n} k = \frac{n(n+1)}{2}$. This is a specific case of an arithmetic series, where the difference between consecutive terms is constant.
Summation of a Constant: The sum of a constant $c$ over $n$ terms is simply $cn$.
Simplification of Fractions: When adding or subtracting fractions, a common denominator is required. Multiplying by an appropriate form of 1 (e.g., $\frac{2}{2}$) can help achieve a common denominator without changing the value of the fractions.
Algebraic Manipulation: The problem requires algebraic manipulation, including distributing constants through a summation, combining like terms, and simplifying expressions.
Multiple Representations of Numbers: The final answer can be presented in different forms, such as an exact fraction, a decimal, or a mixed number, depending on the context or preference.