Evaluate the Summation sum from i=1 to 10 of 9i-3
The problem asks for an evaluation of a mathematical summation where the summing expression is given by "9i - 3". The variable "i" acts as the summation index, which starts from 1 and continues to 10. The task is to calculate the total of this expression for each integer value of "i" in the specified range and then add up all those individual calculations to find the final sum.
$\sum_{i = 1}^{10} 9 i - 3$
Decompose the given summation into two separate summations using the distributive property of summation: $\sum_{i = 1}^{10} (9i - 3) = 9\sum_{i = 1}^{10} i - \sum_{i = 1}^{10} 3$
Calculate $9\sum_{i = 1}^{10} i$.
Use the arithmetic series sum formula: $\sum_{i = 1}^{n} i = \frac{n(n + 1)}{2}$
Plug in the upper limit of the summation and include the coefficient: $9 \left( \frac{10(10 + 1)}{2} \right)$
Perform the arithmetic operations.
Combine $10$ and $1$: $9 \times \frac{10 \cdot 11}{2}$
Calculate $10 \times 11$: $9 \left( \frac{110}{2} \right)$
Divide $110$ by $2$: $9 \times 55$
Multiply $9$ by $55$: $495$
Compute $\sum_{i = 1}^{10} -3$.
Apply the constant series sum formula: $\sum_{i = 1}^{n} c = c \cdot n$
Insert the given values: $(-3) \cdot 10$
Calculate the product of $-3$ and $10$: $-30$
Combine the results from the two summations: $495 - 30$
Subtract $30$ from $495$ to get the final result: $465$
The problem involves evaluating a finite arithmetic series, which is a summation of terms in a sequence where each term after the first is obtained by adding a constant difference to the previous term. The specific series in question is a linear combination of an arithmetic series and a constant series.
Key points to remember when solving such problems include:
Distributive Property of Summation: This property allows us to split a summation of terms into separate summations if the terms are being added or subtracted. For example, $\sum (a_i + b_i) = \sum a_i + \sum b_i$.
Arithmetic Series Sum Formula: The sum of the first $n$ natural numbers is given by $\sum_{i = 1}^{n} i = \frac{n(n + 1)}{2}$. This formula is derived from the observation that the sum of the first and the last term, the second and the second-to-last term, and so on, are all equal to $n + 1$, and there are $\frac{n}{2}$ such pairs.
Constant Series Sum Formula: The sum of a constant $c$ over $n$ terms is simply $c$ multiplied by the number of terms: $\sum_{i = 1}^{n} c = c \cdot n$.
Simplification: After applying the formulas, simplifying the expressions step by step is crucial to avoid mistakes and to make the calculation easier.
Combining Results: After evaluating each part of the summation separately, the final step is to combine the results to get the answer to the original problem.