Find dy/dx 4x^3+x^2y-xy^3=1
The question asks for the derivative of y with respect to x (dy/dx) for the given implicit function 4x^3 + x^2y - xy^3 = 1. This requires using implicit differentiation to find the slope of the curve at any point (x, y) that satisfies the equation. Implicit differentiation is necessary here because the function is not given explicitly as y in terms of x (i.e., y = f(x)), but rather both variables are mixed together on one side of the equation.
$4 x^{3} + x^{2} y - x y^{3} = 1$
Apply the derivative operator to both sides of the equation: $\frac{d}{dx}(4x^3 + x^2y - xy^3) = \frac{d}{dx}(1)$.
Take the derivative term by term on the left side.
Use the Sum Rule to separate the derivatives: $\frac{d}{dx}(4x^3) + \frac{d}{dx}(x^2y) + \frac{d}{dx}(-xy^3)$.
Find the derivative of $4x^3$.
Extract the constant $4$ and differentiate $x^3$: $4\frac{d}{dx}(x^3) + \frac{d}{dx}(x^2y) + \frac{d}{dx}(-xy^3)$.
Apply the Power Rule to $x^3$: $4(3x^2) + \frac{d}{dx}(x^2y) + \frac{d}{dx}(-xy^3)$.
Simplify the result: $12x^2 + \frac{d}{dx}(x^2y) + \frac{d}{dx}(-xy^3)$.
Differentiate $x^2y$.
Use the Product Rule: $x^2\frac{d}{dx}(y) + y\frac{d}{dx}(x^2)$.
Recognize $\frac{d}{dx}(y)$ as $\frac{dy}{dx}$.
Apply the Power Rule to $x^2$: $2x$.
Combine the terms: $12x^2 + x^2\frac{dy}{dx} + 2xy + \frac{d}{dx}(-xy^3)$.
Differentiate $-xy^3$.
Factor out the constant $-1$: $-1\frac{d}{dx}(xy^3)$.
Apply the Product Rule: $-x\frac{d}{dx}(y^3) - y^3\frac{d}{dx}(x)$.
Use the Chain Rule for $y^3$.
Substitute $u$ for $y$: $-x(3u^2\frac{d}{dx}(y)) - y^3$.
Apply the Power Rule to $u^3$: $3u^2$.
Replace $u$ with $y$: $-x(3y^2\frac{dy}{dx}) - y^3$.
Recognize $\frac{d}{dx}(x)$ as $1$.
Simplify the expression: $-3xy^2\frac{dy}{dx} - y^3$.
Combine all terms: $12x^2 + x^2\frac{dy}{dx} + 2xy - 3xy^2\frac{dy}{dx} - y^3$.
Simplify the entire derivative expression.
Combine like terms: $12x^2 + x^2\frac{dy}{dx} + 2xy - 3xy^2\frac{dy}{dx} - y^3$.
Reorder terms for clarity: $12x^2 + x^2\frac{dy}{dx} + 2xy - y^3 - 3xy^2\frac{dy}{dx}$.
Final simplified left side: $12x^2 + (x^2 - 3xy^2)\frac{dy}{dx} + 2xy - y^3$.
The derivative of a constant is zero: $\frac{d}{dx}(1) = 0$.
Combine the derivatives to form the differential equation: $12x^2 + (x^2 - 3xy^2)\frac{dy}{dx} + 2xy - y^3 = 0$.
Isolate $\frac{dy}{dx}$ to solve for the derivative.
Move all terms not containing $\frac{dy}{dx}$ to the other side: $(x^2 - 3xy^2)\frac{dy}{dx} = y^3 - 12x^2 - 2xy$.
Factor out $\frac{dy}{dx}$ from the left side: $\frac{dy}{dx}(x^2 - 3xy^2) = y^3 - 12x^2 - 2xy$.
Divide both sides by $(x^2 - 3xy^2)$ to solve for $\frac{dy}{dx}$.
Perform the division: $\frac{dy}{dx} = \frac{y^3 - 12x^2 - 2xy}{x^2 - 3xy^2}$.
Simplify the right side if necessary.
Final expression for $\frac{dy}{dx}$: $\frac{dy}{dx} = \frac{y^3 - 12x^2 - 2xy}{x^2 - 3xy^2}$.
The derivative $\frac{dy}{dx}$ is now expressed in terms of $x$ and $y$.
Sum Rule: The derivative of a sum of functions is the sum of their derivatives.
Product Rule: The derivative of a product of two functions $f(x)g(x)$ is $f'(x)g(x) + f(x)g'(x)$.
Power Rule: The derivative of $x^n$ with respect to $x$ is $nx^{n-1}$.
Chain Rule: The derivative of a composite function $f(g(x))$ is $f'(g(x))g'(x)$.
Constant Multiple Rule: The derivative of a constant times a function is the constant times the derivative of the function.
Implicit Differentiation: When a function is not given explicitly as $y=f(x)$, but instead is given in a form that relates $x$ and $y$, we differentiate both sides of the equation with respect to $x$ and solve for $\frac{dy}{dx}$.
Simplification: After taking the derivative, it is often necessary to simplify the expression by combining like terms, factoring, and reducing fractions.