Find dy/dx y = natural log of sin(x)
The given problem is asking for the derivative of the function y with respect to x, where y is defined as the natural logarithm of the sine of x. In mathematical terms, the derivative dy/dx represents the rate at which the function y changes as x changes. The expression "natural log of sin(x)" refers to the logarithm to the base e (Euler's number, which is approximately 2.71828) of the sine function of x. This problem involves applying calculus techniques, specifically differentiation rules, to find the derivative of a composition of two functions: the sine function and the natural logarithm function.
$y = ln \left(\right. sin \left(\right. x \left.\right) \left.\right)$
Apply differentiation to both sides of the equation with respect to $x$: $\frac{d}{dx}(y) = \frac{d}{dx}(\ln(\sin(x)))$.
The derivative of $y$ with respect to $x$ is denoted as $\frac{dy}{dx}$.
Proceed to differentiate the natural logarithm of the sine function.
Invoke the chain rule for differentiation: $\frac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)$, where $f(x) = \ln(x)$ and $g(x) = \sin(x)$.
Introduce a substitution $u = \sin(x)$ to facilitate the application of the chain rule: $\frac{d}{du}[\ln(u)] \cdot \frac{d}{dx}[\sin(x)]$.
Compute the derivative of $\ln(u)$ with respect to $u$: $\frac{1}{u} \cdot \frac{d}{dx}[\sin(x)]$.
Substitute back $u$ with $\sin(x)$: $\frac{1}{\sin(x)} \cdot \frac{d}{dx}[\sin(x)]$.
Express $\frac{1}{\sin(x)}$ as $\csc(x)$: $\csc(x) \cdot \frac{d}{dx}[\sin(x)]$.
Identify the derivative of $\sin(x)$ with respect to $x$ as $\cos(x)$: $\csc(x) \cdot \cos(x)$.
Simplify the expression.
Rearrange the factors: $\cos(x) \cdot \csc(x)$.
Rewrite $\csc(x)$ using sine and cosine: $\cos(x) \cdot \frac{1}{\sin(x)}$.
Combine the cosine and reciprocal sine terms: $\frac{\cos(x)}{\sin(x)}$.
Translate $\frac{\cos(x)}{\sin(x)}$ into cotangent: $\cot(x)$.
Formulate the final equation by equating the left-hand side to the right-hand side: $y = \cot(x)$.
Replace $y$ with $\frac{dy}{dx}$ to complete the differentiation: $\frac{dy}{dx} = \cot(x)$.
The problem involves finding the derivative of a function $y$ with respect to $x$, where $y$ is the natural logarithm of the sine of $x$. The solution employs several key concepts in calculus:
Differentiation: The process of finding the derivative, which measures how a function changes as its input changes.
Chain Rule: A fundamental theorem in calculus used to differentiate compositions of functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
Natural Logarithm: The logarithm to the base $e$, where $e$ is Euler's number, approximately equal to 2.71828. The derivative of $\ln(x)$ with respect to $x$ is $\frac{1}{x}$.
Trigonometric Functions and Their Derivatives: The sine function, $\sin(x)$, has a derivative of $\cos(x)$, and the cosecant function, $\csc(x)$, is the reciprocal of $\sin(x)$. The cotangent function, $\cot(x)$, is the reciprocal of the tangent function and can also be expressed as $\frac{\cos(x)}{\sin(x)}$.
Simplification: The process of rewriting an expression in a simpler or more easily usable form. In this case, it involves recognizing and using trigonometric identities to simplify the expression.
By applying these concepts, the problem is solved through a step-by-step differentiation process, leading to the final derivative $\frac{dy}{dx} = \cot(x)$.