Problem

Find dy/dx y=9xarcsin(x)

The given problem is asking for the derivative of the function y with respect to x, where y is defined as the product of the constant 9, the variable x, and the inverse sine function (arcsin) of x. The notation dy/dx represents the derivative of y with respect to x, which is the rate at which y changes with a small change in x. In calculus, this process of finding the derivative is known as differentiation. The question is essentially asking you to apply the rules of differentiation, such as the product rule and the chain rule, to find the expression for the derivative of the given function.

$y = 9 x arcsin \left(\right. x \left.\right)$

Answer

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Solution:

Step:1

Apply the differentiation operator to both sides of the given function: $\frac{d}{dx}(y) = \frac{d}{dx}(9x\arcsin(x))$

Step:2

The derivative of $y$ with respect to $x$ is denoted as $\frac{dy}{dx}$.

Step:3

Proceed to differentiate the expression on the right-hand side.

Step:3.1

Recognize that the constant $9$ can be factored out of the differentiation process: $9\frac{d}{dx}(x\arcsin(x))$

Step:3.2

Apply the product rule for differentiation: $\frac{d}{dx}(uv) = u\frac{dv}{dx} + v\frac{du}{dx}$, where $u = x$ and $v = \arcsin(x)$: $9\left(x\frac{d}{dx}(\arcsin(x)) + \arcsin(x)\frac{d}{dx}(x)\right)$

Step:3.3

Find the derivative of $\arcsin(x)$ with respect to $x$: $9\left(x\frac{1}{\sqrt{1 - x^2}} + \arcsin(x)\frac{d}{dx}(x)\right)$

Step:3.4

Utilize the power rule for differentiation.

Step:3.4.1

Combine terms involving $x$ and $\frac{1}{\sqrt{1 - x^2}}$: $9\left(\frac{x}{\sqrt{1 - x^2}} + \arcsin(x)\frac{d}{dx}(x)\right)$

Step:3.4.2

Differentiate $x$ using the power rule: $\frac{d}{dx}(x^n) = nx^{n-1}$, where $n = 1$: $9\left(\frac{x}{\sqrt{1 - x^2}} + \arcsin(x) \cdot 1\right)$

Step:3.4.3

Simplify the multiplication of $\arcsin(x)$ by $1$: $9\left(\frac{x}{\sqrt{1 - x^2}} + \arcsin(x)\right)$

Step:3.5

Simplify the expression.

Step:3.5.1

Apply the distributive property to combine like terms: $9\frac{x}{\sqrt{1 - x^2}} + 9\arcsin(x)$

Step:3.5.2

Factor out the constant $9$: $\frac{9x}{\sqrt{1 - x^2}} + 9\arcsin(x)$

Step:4

Express the derivative of $y$ with respect to $x$: $y' = \frac{9x}{\sqrt{1 - x^2}} + 9\arcsin(x)$

Step:5

Replace $y$ with $\frac{dy}{dx}$ in the final result: $\frac{dy}{dx} = \frac{9x}{\sqrt{1 - x^2}} + 9\arcsin(x)$

Knowledge Notes:

The problem involves finding the derivative of a function that is a product of a constant, a variable, and an inverse trigonometric function. The solution requires knowledge of several calculus concepts:

  1. Derivative Notation: $\frac{d}{dx}$ represents the differentiation operator with respect to $x$.

  2. Product Rule: A rule for differentiating products of two functions, given by $\frac{d}{dx}(uv) = u\frac{dv}{dx} + v\frac{du}{dx}$.

  3. Derivative of Inverse Trigonometric Functions: Specifically, the derivative of $\arcsin(x)$ is $\frac{1}{\sqrt{1 - x^2}}$.

  4. Power Rule: A basic rule for differentiation, stating that the derivative of $x^n$ is $nx^{n-1}$.

  5. Simplification: Combining like terms and applying algebraic rules to express the derivative in its simplest form.

These concepts are fundamental in differential calculus and are often used in combination to solve more complex differentiation problems.

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