Evaluate the Summation sum from x=0 to 1 of 2x-4
The question asks you to determine the result of adding up the values generated by the expression "2x-4" for every integer value of x from 0 to 1. This is a mathematical summation problem, often denoted with the sigma notation, where you need to substitute the values of x into the expression and then add the results to find the sum.
$\sum_{x = 0}^{1} 2 x - 4$
Calculate the terms of the series by substituting the values of $x$. For $x = 0$ and $x = 1$, the terms are $2 \cdot 0 - 4$ and $2 \cdot 1 - 4$ respectively.
For the first term, multiply $2$ by $0$ to get $0$, and for the second term, multiply $2$ by $1$ to get $2$.
The series now looks like: $0 - 4 + 2 - 4$.
Combine the constants by adding and subtracting them in sequence.
First, subtract $4$ from $0$ to get $-4$.
Next, add $2$ to get $-2$.
Finally, subtract $4$ to get the sum: $-6$.
The final result of the summation is $-6$.
To evaluate the summation of a series, you follow these steps:
Expansion: Write out each term of the series by substituting the values of the variable into the given expression.
Simplification: Perform the operations indicated in each term, such as multiplication, addition, or subtraction.
Combination: Add or subtract the simplified terms to find the total sum.
In this problem, the series is a simple arithmetic expression involving multiplication and subtraction. The summation is over a finite and small range, so it can be done by direct calculation without the need for more complex summation formulas or techniques.
The expression $2x - 4$ is a linear function of $x$. When evaluating the summation of a linear function over a range, you can substitute each value of $x$ within the range and then perform the arithmetic operations to find the sum.
In LaTeX, multiplication is often denoted by $\cdot$, subtraction by $-$, and addition by $+$. When writing series or summations, the sigma notation $\sum$ is used, but in this case, since the range is small, it's straightforward to write out each term explicitly.