Find the vertex form of the parabola given by the equation (y = 2x^2 - 12x + 20).

Question

Accepted Answer

Step:1 ：Rewrite the equation in the form (y = a(x-h)^2 + k).Step:2 ：Factor out the leading coefficient from the first two terms: (y = 2(x^2 - 6x) + 20).Step:3 ：Complete the square on the (x) terms: (y = 2[(x - 3)^2 - 9] + 20).Step:4 ：Simplify to find the vertex form: (y = 2(x - 3)^2 - 18 + 20 = 2(x - 3)^2 + 2).

Answer

Step: 1 ：Rewrite the equation in the form (y = a(x-h)^2 + k).Step: 2 ：Factor out the leading coefficient from the first two terms: (y = 2(x^2 - 6x) + 20).Step: 3 ：Complete the square on the (x) terms: (y = 2[(x - 3)^2 - 9] + 20).Step: 4 ：Simplify to find the vertex form: (y = 2(x - 3)^2 - 18 + 20 = 2(x - 3)^2 + 2).

Find the vertex form of the parabola given by the equation $y = 2 x^{2} - 12 x + 20$ .

Answer

Popular Problems

Find the vertex form of the parabola given by the equation y=2x2−12x+20.

Answer

Popular Problems

Find the vertex form of the parabola given by the equation $y = 2 x^{2} - 12 x + 20$ .