$\int e^{8 x} d x$
Therefore, the result is correct and the integral of \(e^{8x} dx\) is \(\boxed{\frac{1}{8}e^{8x} + C}\)
Step 1 :Given the integral \(\int e^{8x} dx\)
Step 2 :We use the rule of integration for exponential functions, which states that the integral of \(e^{ax} dx\) is \(\frac{1}{a}e^{ax} + C\), where \(C\) is the constant of integration.
Step 3 :So, for the integral of \(e^{8x} dx\), \(a = 8\).
Step 4 :Therefore, \(\int e^{8x} dx = \frac{1}{8}e^{8x} + C\)
Step 5 :To check if this result is correct, we differentiate it and see if we get back the original function \(e^{8x}\).
Step 6 :The derivative of \(\frac{1}{8}e^{8x} + C\) is \(e^{8x}\), which is indeed the original function.
Step 7 :Therefore, the result is correct and the integral of \(e^{8x} dx\) is \(\boxed{\frac{1}{8}e^{8x} + C}\)