Factor the expression (64x^{3}-125)

Question

Accepted Answer

Step:1 ：Step 1: Recognize that this is a difference of cubes and it can be written as ((4x)^{3} - (5)^{3})Step:2 ：Step 2: Apply the formula for factoring a difference of cubes, which is (a^{3} - b^{3} = (a - b)(a^{2} + ab + b^{2})). Here, a = 4x and b = 5Step:3 ：Step 3: Substitute a and b into the formula to get ((4x - 5)((4x)^{2} + 4x*5 + (5)^{2}) = (4x - 5)(16x^{2} + 20x + 25))

Answer

Step: 1 ：Step 1: Recognize that this is a difference of cubes and it can be written as ((4x)^{3} - (5)^{3})Step: 2 ：Step 2: Apply the formula for factoring a difference of cubes, which is (a^{3} - b^{3} = (a - b)(a^{2} + ab + b^{2})). Here, a = 4x and b = 5Step: 3 ：Step 3: Substitute a and b into the formula to get ((4x - 5)((4x)^{2} + 4x*5 + (5)^{2}) = (4x - 5)(16x^{2} + 20x + 25))

Factor the expression \(64x^{3}-125\)

Answer

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