EXAM 2 Review
Question 19 of
Find the equation of the line with the given slope and containing the given point.
Slope $-\frac{1}{10} ;$ through $(-3,0)$
The equation of the line is $\square$.
(Simplify your answer. Type your answer in slope-intercept form.)
Answer
\(\boxed{y = -\frac{1}{10}x - 0.3}\) is the equation of the line.
Step 1 ：We are given the slope \(m = -\frac{1}{10}\) and a point on the line \((-3,0)\).
Step 2 ：We can substitute these values into the equation \(y = mx + b\) to solve for \(b\).
Step 3 ：Substituting the given values, we get \(0 = -\frac{1}{10}*(-3) + b\).
Step 4 ：Solving for \(b\), we find that \(b = -0.3\).
Step 5 ：Finally, we can write the equation of the line in slope-intercept form.
Step 6 ：\(\boxed{y = -\frac{1}{10}x - 0.3}\) is the equation of the line.
