Problem

Find the vertical asymptote.
\[
\begin{array}{l}
y=\frac{3 x-3}{x+1} \\
x=[?]
\end{array}
\]

Answer

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Answer

Final Answer: The vertical asymptote is \(\boxed{x = -1}\).

Steps

Step 1 :Given the function \(y=\frac{3x-3}{x+1}\), we are asked to find the vertical asymptote.

Step 2 :The vertical asymptote of a rational function is found by setting the denominator equal to zero and solving for \(x\).

Step 3 :So, we set \(x + 1 = 0\).

Step 4 :Solving for \(x\), we find that \(x = -1\).

Step 5 :Final Answer: The vertical asymptote is \(\boxed{x = -1}\).

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