Question 2
1 pt
1
Details
A group of people were asked if they had run a red light in the last year. 404 responded "yes", and 202 responded "no".
Find the probability that if a person is chosen at random, they have run a red light in the last year.
Give your answer as a fraction or decimal
Check Answer
Final Answer: The probability that a person chosen at random has run a red light in the last year is approximately \(\boxed{0.67}\) or \(\boxed{\frac{2}{3}}\) in fraction form.
Step 1 :The question is asking for the probability that a person chosen at random has run a red light in the last year. To find this, we need to divide the number of people who responded 'yes' by the total number of people surveyed.
Step 2 :Let's denote the number of 'yes' responses as \(y\), the number of 'no' responses as \(n\), and the total number of responses as \(t\).
Step 3 :Given that \(y = 404\), \(n = 202\), we can calculate \(t\) as \(t = y + n = 404 + 202 = 606\).
Step 4 :The probability \(p\) that a person chosen at random has run a red light in the last year is then given by \(p = \frac{y}{t} = \frac{404}{606} = 0.6666666666666666\).
Step 5 :Final Answer: The probability that a person chosen at random has run a red light in the last year is approximately \(\boxed{0.67}\) or \(\boxed{\frac{2}{3}}\) in fraction form.