Evaluate the expression for $x = 2$ and $y = 4$ .
$16 x^{0} + 2 x^{2} \cdot y^{- 1}$

Answer

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Answer

So, the evaluated expression for $x = 2$ and $y = 4$ is $18$ .

Steps

Step 1 ：Substitute the given values of x and y into the expression. So, we have $16 \cdot 2^{0} + 2 \cdot 2^{2} \cdot 4^{- 1}$ .

Step 2 ：According to the order of operations, we first evaluate the exponentiation. So, we get $16 \cdot 1 + 2 \cdot 4 \cdot 0.25$ .

Step 3 ：Next, we perform the multiplication. So, we get $16 + 2$ .

Step 4 ：Finally, we perform the addition. So, we get 18.

Step 5 ：So, the evaluated expression for $x = 2$ and $y = 4$ is $18$ .