Find the vertex.
$f (x) = 4 x^{2} - 16 x + 10$
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Answer

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Answer

The vertex of the function $f (x) = 4 x^{2} - 16 x + 10$ is $(2, - 6)$

Steps

Step 1 ：Given the function $f (x) = 4 x^{2} - 16 x + 10$

Step 2 ：The vertex of a parabola given by the equation $f (x) = a x^{2} + b x + c$ is given by the point $- \frac{b}{2 a}, f (- \frac{b}{2 a})$

Step 3 ：In this case, $a = 4$ and $b = - 16$ , so the x-coordinate of the vertex is $- \frac{- 16}{2 * 4} = 2$

Step 4 ：We can substitute $x = 2$ into the equation to find the y-coordinate of the vertex

Step 5 ：The vertex of the function $f (x) = 4 x^{2} - 16 x + 10$ is $(2, - 6)$