Problem

Find all solutions in the interval $[0,2 \pi)$
\[
\tan ^{2} x=1
\]

Answer

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Answer

Final Answer: The solutions to the equation \(\tan^2 x = 1\) in the interval \([0, 2\pi)\) are \(\boxed{\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}}\).

Steps

Step 1 :Given the equation \(\tan^2 x = 1\), we can simplify this to \(\tan x = \pm 1\).

Step 2 :We are looking for the solutions in the interval \([0, 2\pi)\).

Step 3 :The angles in this interval for which the tangent is either 1 or -1 are \(\frac{\pi}{4}\), \(\frac{3\pi}{4}\), \(\frac{5\pi}{4}\), and \(\frac{7\pi}{4}\).

Step 4 :We can confirm these are the solutions by calculating the tangent of these angles, which are approximately 1, -1, 1, and -1 respectively.

Step 5 :Final Answer: The solutions to the equation \(\tan^2 x = 1\) in the interval \([0, 2\pi)\) are \(\boxed{\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}}\).

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