Let $F(x)=x^{2}-1$ and $G(x)=2-x$
Find $(F+G)(x)$.
\[
(F+G)(x)=\square
\]
Final Answer: \((F+G)(x)=\boxed{x^{2} - x + 1}\)
Step 1 :Let \(F(x)=x^{2}-1\) and \(G(x)=2-x\).
Step 2 :Find \((F+G)(x)\).
Step 3 :We need to add the two functions \(F(x)\) and \(G(x)\) together. This means we add \(x^{2}-1\) and \(2-x\) together.
Step 4 :We can do this by simply adding the corresponding terms of the two functions.
Step 5 :The result of adding the functions \(F(x)\) and \(G(x)\) together is \(x^{2} - x + 1\).
Step 6 :Final Answer: \((F+G)(x)=\boxed{x^{2} - x + 1}\)